Bunuel
GMAT40
Hi Bunnel,
Why should it be DST as mentioned by Zarrolou?
If we take st 1 and t 2 together we should be able to get the D:S:T ratio as 1:2:8
Consider an example:
each of its 2 department heads has exactly 3 teachers reporting to her, and that
each teacher has exactly 4 students. How many students are there?
There are 2*3=6 teachers, and since
each teacher has exactly 4 students, then there are 6*4=24 students.
Does this make sense?
If there are 6 teachers and 2 department heads as obtained above then the ratio of T/D = 3/1 which is not possible as given in statement 1, T/D= 2/1
SO T/D can be : 2x/1x ( Statement 1 )
and S/T = 4y/1y ( Statement 2 )
when x = 1 then T = 2 and D =1
So putting y = 2 ( to equate teachers ) we get S= 8 ,T= 2 hence S/D= 8/1
when x = 2 then T = 4 and D=2 putting y = 4 we get S= 16, T=4 hence S/D= 16/2 = 8/1
So it seems the ration of S/D is always 8/1 ,
I also feel answer should be C
We need the ratio and also in the examples provided by Zarrolou the ratio of S/D comes to be 8/1
a-school-district-is-organized-such-that-each-of-its-d-154681.html#p1238106Let me know if I have missed something. Thanks.