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06 Nov 2019, 06:33
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C
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Difficulty:
35%
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Question Stats:
71% (01:45) correct
29%
(01:42)
wrong
based on 253
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A shopkeeper purchased footballs at $10 per football and sold them at a price equal to the purchase price plus a markup. If the markup was 10% of the selling price, what was the shopkeeper's profit in dollars, to the nearest cent, on each football?
A. 0.90
B. 1.00
C. 1.11
D. 2.00
E. 11.11
Are You Up For the Challenge: 700 Level Questions
A. 0.90
B. 1.00
C. 1.11
D. 2.00
E. 11.11
Are You Up For the Challenge: 700 Level Questions
06 Nov 2019, 08:39
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Assume SP of the football=x
\(10+\frac{x}{10}=x\)
x=\(\frac{100}{9}\)
Profit= \(\frac{10}{9}\)=1.11
\(10+\frac{x}{10}=x\)
x=\(\frac{100}{9}\)
Profit= \(\frac{10}{9}\)=1.11
Bunuel
06 Nov 2019, 09:07
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CP = 10$
SP = x
x= 10+10*x/100
x= 100/9
profit = 100/9-10 ; 10/9 ; 1.11
IMO C
SP = x
x= 10+10*x/100
x= 100/9
profit = 100/9-10 ; 10/9 ; 1.11
IMO C
Bunuel
