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26 Mar 2018, 00:11
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E
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Difficulty:
15%
(low)
Question Stats:
86% (01:14) correct
14%
(02:47)
wrong
based on 52
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History
Date
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Not Attempted Yet
A small motor uses 27/8 gallons of gasoline every 15 hours. What is the motor’s fuel consumption rate, in gallons per day?
(A) 0.225
(B) 1.6
(C) 4.8
(D) 5.2
(E) 5.4
(A) 0.225
(B) 1.6
(C) 4.8
(D) 5.2
(E) 5.4
26 Mar 2018, 00:45
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For every 15 hours, gasoline used by a small motor= \(\frac{27}{8}\) gallons
.................1 hour......................................................= \(\frac{27}{8*15}\)
.................24 hour....................................................= \(\frac{27}{8*15}\)*24= \(\frac{27}{5}\)= 5.4
\(Answer: E.\)
.................1 hour......................................................= \(\frac{27}{8*15}\)
.................24 hour....................................................= \(\frac{27}{8*15}\)*24= \(\frac{27}{5}\)= 5.4
\(Answer: E.\)
26 Mar 2018, 20:10
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Bunuel
You can set up a proportion:
\(\frac{Hours}{Hours}=\frac{Gallons}{Gallons}\)
\(\frac{24}{15}=\frac{X}{(\frac{27}{8})}\)
\(\frac{24}{15}=\frac{8X}{27}\)
\(\frac{1}{5}=\frac{X}{27}\)
\(5X = 27\)
\(X = \frac{27}{5}=5.4\) gallons
Answer E
NOTE: The proportion's numbers are easy to cancel. You cannot cancel diagonally. Factor out an 8 from both numerators, thus:\(\frac{3}{15}=\frac{X}{27}\).
Then factor out a 3 from LHS fraction, thus proportion becomes:\(\frac{1}{5}=\frac{X}{27}\)
