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# A store sells kitchen items. In this store, all knives of type X have

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Re: A store sells kitchen items. In this store, all knives of type X have [#permalink]
amanvermagmat wrote:
A store sells kitchen items. In this store, all knives of type X have same price. Also all plates of type P have same price. Danny bought 3 knives of type X and 4 plates of type P from this store. How much did Danny pay for this purchase in dollars?

(1) If Danny had instead bought 6 knives of type X and 2 plates of type P, he would have paid 12 dollars more than what he paid now.

(2) Cost of a knife is 1/3 more than that of a plate.

Statement 2 never says the knife is of type X. Shouldn't the answer be (E) then?
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Re: A store sells kitchen items. In this store, all knives of type X have [#permalink]
ishan92 wrote:
amanvermagmat wrote:
A store sells kitchen items. In this store, all knives of type X have same price. Also all plates of type P have same price. Danny bought 3 knives of type X and 4 plates of type P from this store. How much did Danny pay for this purchase in dollars?

(1) If Danny had instead bought 6 knives of type X and 2 plates of type P, he would have paid 12 dollars more than what he paid now.

(2) Cost of a knife is 1/3 more than that of a plate.

Statement 2 never says the knife is of type X. Shouldn't the answer be (E) then?

Hello

Thank you for noticing, I have edited the second statement.
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Re: A store sells kitchen items. In this store, all knives of type X have [#permalink]
Let the price of each knife be $k and price of each plate be$p.
So, we have to find 3k + 4p.

Considering st.(1) alone:
(6k + 2p) - (3k + 4p) = 12
3k - 2p = 12
Insufficient

Considering st. (2) alone:
k = p + (1/3)p => k = 4p/3
Insufficient

Considering (1) and (2) together:
2 equations and 2 variables. So, equations can be solved.
Sufficient