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chunjuwu
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A telephone company offers a special service to customers 06 Aug 2004, 08:58
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A telephone company offers a special service to customers who make long-distance calls. For an additional monthly charge of $8, all long-distance charges in excess of $16 for a month are reduced by 50 percent. If a customer has long-distance charges of $48 for one month without the special service, how much would the customer have saved by using the special service?

(A)$0

(B) $8

(C)$16

(D)$20

(E)$32



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chunjuwu
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A telephone company offers a special service to customers 06 Aug 2004, 09:36
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Excuse me.

I supposed

8 + 16 + (48-16) * 0.5 = 40

48 - 40 = 8

Is this right?
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venksune
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A telephone company offers a special service to customers 06 Aug 2004, 09:43
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chunjuwu,
You are right.

it has to be

8 + 16 + (48-16) * 0.5 = 40

48-40 = 8.

Absolutely right.
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krish
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A telephone company offers a special service to customers 06 Aug 2004, 16:32
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48-16+8 = $8

I know this is the worst way to explain a math problem. But since you guys have already explained it pretty well... do i need to :-)

--- lazy fella
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A telephone company offers a special service to customers 06 Aug 2004, 17:28
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chunjuwu
Excuse me.

I supposed

8 + 16 + (48-16) * 0.5 = 40

48 - 40 = 8

Is this right?
Show more


Both ways are right chunjuwu.
1) What you did was:
Total the guy actually spent = 48
Total the guy should have spent = extra charge + full amt upto 16 + 1/2 (rest) = 8 + 16 + (48-16) * 0.5 = 40
Prospective savings = 48 - 40 = 8

2) What I did was:
Just calculating the savings only (or rather company's expenditure only):
Company has to pay the 1/2 of rest, but it gets $8 from the guy
So guys savings = company's expenditure = (48-16)/2 - 8 = 8

This method probably saves just a couple of seconds...



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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