GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 18 Oct 2019, 19:12

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# A truck departed from Newton at 11:53 a.m. and arrived in Far City, 2

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 58453
A truck departed from Newton at 11:53 a.m. and arrived in Far City, 2  [#permalink]

### Show Tags

13 Feb 2018, 05:46
00:00

Difficulty:

25% (medium)

Question Stats:

72% (01:48) correct 28% (02:03) wrong based on 114 sessions

### HideShow timer Statistics

A truck departed from Newton at 11:53 a.m. and arrived in Far City, 240 miles away, at 4:41 p.m. on the same day. What was the approximate average speed of the
truck on this trip?

(A) 20 mph

(B) 34 mph

(C) 50 mph

(D) 54 mph

(E) 72 mph

_________________
Intern
Joined: 28 Sep 2017
Posts: 4
GMAT 1: 620 Q43 V36
WE: Business Development (Non-Profit and Government)
Re: A truck departed from Newton at 11:53 a.m. and arrived in Far City, 2  [#permalink]

### Show Tags

13 Feb 2018, 07:42

Simple way to do it is to just add 7 minutes to both start time and arrival time, making it 12:00 and 4:48 pm, making it easily calculate it in hours form -> 4 hours 48 minutes -> 4.8 hours

240 miles/4.8 hours = 50 mph.
Board of Directors
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 4772
Location: India
GPA: 3.5
Re: A truck departed from Newton at 11:53 a.m. and arrived in Far City, 2  [#permalink]

### Show Tags

13 Feb 2018, 08:21
Bunuel wrote:
A truck departed from Newton at 11:53 a.m. and arrived in Far City, 240 miles away, at 4:41 p.m. on the same day. What was the approximate average speed of the
truck on this trip?

(A) 20 mph

(B) 34 mph

(C) 50 mph

(D) 54 mph

(E) 72 mph

11:53 to 12:53 = 1 Hour
12:53 to 1:53 = 1 Hour
1:53 to 2:53 = 1 Hour
2:53 to 3:53 = 1 Hour
3:53 to 4:11 = 18 min

Total we have 258/60 Hr = 4.30 Hours

Final speed is 240 /4.30 = 55.81 Miles/Hour, IMHO (D)

_________________
Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

How to use Search Function in GMAT Club | Rules for Posting in QA forum | Writing Mathematical Formulas |Rules for Posting in VA forum | Request Expert's Reply ( VA Forum Only )
Intern
Joined: 20 Feb 2017
Posts: 3
Re: A truck departed from Newton at 11:53 a.m. and arrived in Far City, 2  [#permalink]

### Show Tags

13 Feb 2018, 12:03
Abhishek009 wrote:
Bunuel wrote:
A truck departed from Newton at 11:53 a.m. and arrived in Far City, 240 miles away, at 4:41 p.m. on the same day. What was the approximate average speed of the
truck on this trip?

(A) 20 mph

(B) 34 mph

(C) 50 mph

(D) 54 mph

(E) 72 mph

11:53 to 12:53 = 1 Hour
12:53 to 1:53 = 1 Hour
1:53 to 2:53 = 1 Hour
2:53 to 3:53 = 1 Hour
3:53 to 4:11 = 18 min

Total we have 258/60 Hr = 4.30 Hours

Final speed is 240 /4.30 = 55.81 Miles/Hour, IMHO (D)

The arrived time is 4:41. So the answer is C: 50 mph
Senior SC Moderator
Joined: 22 May 2016
Posts: 3555
A truck departed from Newton at 11:53 a.m. and arrived in Far City, 2  [#permalink]

### Show Tags

13 Feb 2018, 17:57
Bunuel wrote:
A truck departed from Newton at 11:53 a.m. and arrived in Far City, 240 miles away, at 4:41 p.m. on the same day. What was the approximate average speed of the
truck on this trip?

(A) 20 mph

(B) 34 mph

(C) 50 mph

(D) 54 mph

(E) 72 mph

11:53 a.m. to 12:00 = 7 minutes
12:00 to 4:00 p.m. = 4 hours
4:00 to 4:41 = 41 minutes
41 + 7 = 48 minutes total
4 hours total

48 minutes = $$\frac{48}{60} = \frac{4}{5} = 0.8$$ hours
4 hours + 0.8 hours = 4.8 hours = time taken

$$\frac{D}{T}= R$$

$$\frac{240miles}{4.8hrs}= 50$$
miles per hour

To make the arithmetic faster, use $$4\frac{4}{5}$$ hours = $$\frac{24}{5}$$ hours
$$\frac{240}{\frac{24}{5}} = 240 * \frac{5}{24} = 50$$ mph
_________________
SC Butler has resumed! Get two SC questions to practice, whose links you can find by date, here.

Instructions for living a life. Pay attention. Be astonished. Tell about it. -- Mary Oliver
Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 8109
Location: United States (CA)
Re: A truck departed from Newton at 11:53 a.m. and arrived in Far City, 2  [#permalink]

### Show Tags

16 Feb 2018, 10:29
Bunuel wrote:
A truck departed from Newton at 11:53 a.m. and arrived in Far City, 240 miles away, at 4:41 p.m. on the same day. What was the approximate average speed of the
truck on this trip?

(A) 20 mph

(B) 34 mph

(C) 50 mph

(D) 54 mph

(E) 72 mph

The trip took 4 hours and 48 minutes = 4 hours and 48/60 hours = 4 hours and 4/5 hours = 24/5 hours.

Thus, the average speed is 240/(24/5) = 1200/24 = 50 mph.

_________________

# Scott Woodbury-Stewart

Founder and CEO

Scott@TargetTestPrep.com
122 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

Intern
Joined: 16 May 2017
Posts: 48
GPA: 3.8
WE: Medicine and Health (Health Care)
Re: A truck departed from Newton at 11:53 a.m. and arrived in Far City, 2  [#permalink]

### Show Tags

21 Oct 2018, 03:51
Time taken by Newton to travel = 11:53 am - 4:41 pm= 4 hours 48 mins= 24/5 hrs
Distance= 280 miles

Speed= distance/time= 280*5/24= 50 mph

Ans(C)
Re: A truck departed from Newton at 11:53 a.m. and arrived in Far City, 2   [#permalink] 21 Oct 2018, 03:51
Display posts from previous: Sort by