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Re: ABC is a triangle. D is a point on AB such that AD:DB=3:2 . E is the [#permalink]
nick1816 wrote:
Draw a line, DF parallel to AE.
BDF is similar to BAE
AD/BD = FE/BF
3/2=FE/BF
if FE=3k, then BF=2k

E is the midpoint of BC, Hence EC= 3k+2k=5k

Also, CPE is similar to CDF
CP/PD = EC/FE
CP/PD= 5k/3k=5/3


abhishek31 wrote:
Hi, can anyone offer a solution to the problem?


Hello nick1816!

How do we know that we are taking the correct ocrresponding sides?

Kind regards!
GMAT Club Bot
Re: ABC is a triangle. D is a point on AB such that AD:DB=3:2 . E is the [#permalink]
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