Jinglander
Can someone please derive and explain how to find the angel size inscribed in a circle when knowing the radius and arc. This would be a non central angle
If you know the length \(L\) of the minor arc and radius, the inscribed angle is: \(Angle=\frac{90L}{\pi{r}}\).
The way to derive the above formula:Length of minor arc is \(L= \frac{Central-Angle}{360}* Circumference\) --> \(L= \frac{Central-Angle}{360}* 2\pi{r}\).
The Central Angle Theorem states that the measure of inscribed angle is always half the measure of the central angle.
So, \(L= \frac{2*Inscribed-Angle}{360}* 2\pi{r}\) --> \(L= \frac{Inscribed-Angle}{90}*\pi{r}\) --> \(Inscribed-Angle=\frac{90L}{\pi{r}}\).
For more on this issue please check Circles chapter of Math Book (link in my signature).
Hope it helps.