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Manager
Joined: 23 Jan 2008
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25 Jan 2008, 12:06
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Ina certain game , a large conatiner is filled with red, yellow, green and blue beads worth, respectively, 7,5,3,and 2 points each. A number of beads are then removed from the container. If the product of the values of the removed beads is 147,000, how many red beads were removed?

A 5
B 4
C 3
D 2
E 0

Last edited by blog on 25 Jan 2008, 14:08, edited 1 time in total.

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VP
Joined: 22 Oct 2006
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Schools: Chicago Booth '11

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25 Jan 2008, 14:44
1
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D) 2

147,000 = 2^3 * 3^1 * 5^3 * 7^ 2

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Intern
Joined: 07 Jan 2007
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25 Jan 2008, 12:18
147000 = 2*2*3*3*5*5*5*7*7

Therefore the answer is D) 2.

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Manager
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25 Jan 2008, 13:56
147000 is euqal to 7(Red) * 5( Yellow) * 3(Green) * 2(Blue) where Red, Yellow Green Blue is the # of respective color beads

Case1)
147000 = 7(Red) * 5(Yellow) * 3(Green) * 2 ( Blue)

Let # of Yellow be 7 green be 2 blue be 10

ie 147000 = 7 Red * 35 * 6 * 20
Red = 5

Case 2)
147000 = 7(Red) * 5(Yellow) * 3(Green) * 2 ( Blue)
Let # of Yellow be 7 green be 5 blue be 5
ie 147000 = 7 Red * 35 * 15 * 10
Red = 4

Similarly i can prove Red to be 3/2 and even zero those who wonder how red = 3 ie by picking no green beads ... ie green = 0 ... u do the math ....

someone explain the flaw in my explination

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Manager
Joined: 23 Jan 2008
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25 Jan 2008, 14:53
terp26 wrote:
D) 2

147,000 = 2^3 * 3^1 * 5^3 * 7^ 2

cool got it ... my mistake was not realizing even each similar color ball value is also multiplied not just distinct one ///..... just made the simple question tough by my mistake

Thanks
-B

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