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1. Q. can be answered using statement 1 alone. 2. Q. can be answered using statement 2 alone. 3. Statement 1 & 2 both are needed to answer the Q. 4. Q. can’t be answered even using both the statements
Q. Given that, X and Y are non negative. What is the value of X? 1. 2X+2Y =20
a) 1 b) 2 c) 3 d) 4 I have conflict of answer.
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1. Q. can be answered using statement 1 alone. 2. Q. can be answered using statement 2 alone. 3. Statement 1 & 2 both are needed to answer the Q. 4. Q. can’t be answered even using both the statements
Q. Given that, X and Y are non negative. What is the value of X? 1. 2X+2Y <=40 2. X-2Y>=20
a) 1 b) 2 c) 3 d) 4 I have conflict of answer.
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1. x+y<=20 x=0; y=1; x=1; y=1 Not Sufficient.
2. x-2y>=20 x=20; y=0; x=21; y=0 Not Sufficient.
Both; x+y-(x-2y)<=20-20 3y<=0 y<=0 OR y=0, as y is non-negative.
1. Q. can be answered using statement 1 alone. 2. Q. can be answered using statement 2 alone. 3. Statement 1 & 2 both are needed to answer the Q. 4. Q. can’t be answered even using both the statements
Q. Given that, X and Y are non negative. What is the value of X? 1. 2X+2Y =20
a) 1 b) 2 c) 3 d) 4 I have conflict of answer.
Show more
This is how I deal with this question: If I am to get a value of X from 2 inequalities, I will get it from the border conditions. So more than anything, I will focus on the 'equal to' sign. It is clear that either one of the inequalities will not give me the value of X. I have to see whether both together give me a value. 1. X + Y = 20 When Y is added to X, it is LESS than or equal to 20. When twice of Y is subtracted from X, it is GREATER than or equal to 20! Since Y cannot be negative, it must be 0 to give 20 in both cases. That is the only way in which both these conditions can be met. Hence, X must be 20.
fluke: Of course, your solution is absolutely correct and spot on. I am giving this method only to encourage you guys to think in terms of the 'big picture'. Very often, it helps you logically deduce your answer without much mathematical work.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.