niks18 wrote:

Consider three real numbers, \(x\), \(y\), and \(z\). Is \(z\) the smallest of these numbers?

A. \(x\) is greater than at least one of \(y\) and \(z\)

B. \(y\) is greater than at least one of \(x\) and \(z\)

OEStatement A: implies \(x>y\) or \(x>z\) or \(x>y\) and \(z\). Hence

InsufficientStatement B: implies \(y>x\) or \(y>z\) or \(y>x\) and \(z\). Hence

InsufficientCombining both statements, we can get \(y>x >z\)

or \(x>y>z\). In either case \(z\) is the smallest.

Option

C