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Updated on: 11 Jul 2019, 05:16
Originally posted by Bunuel on 21 May 2017, 11:13.
Last edited by Sajjad1994 on 11 Jul 2019, 05:16, edited 1 time in total.
Last edited by Sajjad1994 on 11 Jul 2019, 05:16, edited 1 time in total.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
70% (01:43) correct
30%
(01:44)
wrong
based on 207
sessions
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Time
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Not Attempted Yet
Cyclist M leaves point P at 12 noon and travels at constant velocity in a straight path. Cyclist N leaves point P at 2 PM, travels the same path at a constant velocity, and overtakes M at 4 PM. What was the average speed of N?
(1) The velocity of Cyclist M was 20 miles per hour.
(2) When Cyclist N overtook Cyclist M, both had traveled 60 miles.
(1) The velocity of Cyclist M was 20 miles per hour.
(2) When Cyclist N overtook Cyclist M, both had traveled 60 miles.
Source: Nova GMAT
Difficulty Level: 600
Difficulty Level: 600
24 May 2017, 23:26
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When two bodies move in same direction, their relative speed = difference of their speeds
Let velocity of M be m and let velocity of N be n. Their relative speed = n-m
First M moves for 2 hours, let distance covered be D, Then time taken to overtake, t = D/(n-m)
Here N overtakes M in two hours. So D/(n-m) = 2
Statement 1. m=20 mph. So, D = 20*2 = 40 miles So,
40/(n-20) = 2. n = 40 mph. Sufficient
Statement 2. N overtook M at 4 pm and at that time, both had travelled 60 miles.
M covers 60 miles from 12 to 4 pm. So m=60/4 = 15 mph
N covers 60 miles from 2 pm to 4 pm. So n = 60/2 = 30 mph.
Sufficient
Hence D answer
(Though I am confused because answers are coming different from the two statements. In GMAT, when the answer is 'D', both statements should give the same answer. Maybe I am missing something)
Let velocity of M be m and let velocity of N be n. Their relative speed = n-m
First M moves for 2 hours, let distance covered be D, Then time taken to overtake, t = D/(n-m)
Here N overtakes M in two hours. So D/(n-m) = 2
Statement 1. m=20 mph. So, D = 20*2 = 40 miles So,
40/(n-20) = 2. n = 40 mph. Sufficient
Statement 2. N overtook M at 4 pm and at that time, both had travelled 60 miles.
M covers 60 miles from 12 to 4 pm. So m=60/4 = 15 mph
N covers 60 miles from 2 pm to 4 pm. So n = 60/2 = 30 mph.
Sufficient
Hence D answer
(Though I am confused because answers are coming different from the two statements. In GMAT, when the answer is 'D', both statements should give the same answer. Maybe I am missing something)
General Discussion
23 May 2017, 05:30
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Bunuel
Cyclist M leaves point P at 12 noon and travels at constant velocity in a straight path. Cyclist N leaves point P at 2 PM, travels the same path at a constant velocity, and overtakes M at 4 PM. What was the average speed of N?
(1) The velocity of Cyclist M was 20 miles per hour.
(2) When Cyclist N overtook Cyclist M, both had traveled 60 miles.
(1) The velocity of Cyclist M was 20 miles per hour.
(2) When Cyclist N overtook Cyclist M, both had traveled 60 miles.
it took 2hrs for cyclist N to overtake..
stat1: the relative distance of M and N will be 40 miles.. speed of N is 60,,,suff
stat2: again we can calculate the speed of each,,suff,,
ans D
