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# Distance between Smith's house and office is D km. On Monday, S

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Intern
Joined: 05 Dec 2017
Posts: 21
GPA: 3.35
Distance between Smith's house and office is D km. On Monday, S  [#permalink]

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10 Apr 2018, 01:24
1
00:00

Difficulty:

75% (hard)

Question Stats:

59% (02:10) correct 41% (02:37) wrong based on 85 sessions

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Distance between Smith's house and office is $$D$$ km. On Monday, Smith traveled to his office at $$M$$ km/hr for the first 20 km, and the rest at a speed of $$1.25M$$ km/hr. On, Tuesday, Smith traveled the same distance at a speed of $$M$$ km/hr. what is ratio of time taken by Smith to travel from his house to office on Monday and Tuesday?

(1) $$M = 48$$
(2) $$D = 40$$
Intern
Joined: 31 Jul 2017
Posts: 11
Re: Distance between Smith's house and office is D km. On Monday, S  [#permalink]

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10 Apr 2018, 02:03
On Solving the equation the ratio of Monday to Tuesday is (D+5)/1.25M.
Thus both options are needed to give the rati. Hence, C
DS Forum Moderator
Joined: 21 Aug 2013
Posts: 1428
Location: India
Re: Distance between Smith's house and office is D km. On Monday, S  [#permalink]

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10 Apr 2018, 07:04
1
Jamil1992Mehedi wrote:
Distance between Smith's house and office is $$D$$ km. On Monday, Smith traveled to his office at $$M$$ km/hr for the first 20 km, and the rest at a speed of $$1.25M$$ km/hr. On, Tuesday, Smith traveled the same distance at a speed of $$M$$ km/hr. what is ratio of time taken by Smith to travel from his house to office on Monday and Tuesday?

(1) $$M = 48$$
(2) $$D = 40$$

time taken on Monday = 20/M + (D-20)/1.25M = (D+5)/1.25M
time taken on Tuesday = D/M

Ratio of these two times = (D+5) / D*1.25 or 4/5 * (D+5)/D
So to solve this question, we just need the value of D, which is given in statement 2.

(Pls check the OA).
Intern
Joined: 29 Nov 2016
Posts: 35
GMAT 1: 650 Q47 V33
Re: Distance between Smith's house and office is D km. On Monday, S  [#permalink]

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11 Apr 2018, 07:27
Total distance b/w home and office = D.
Monday:-
>1st part:-
Dist1 = 20km
S1 = M
T1 = 20/M
>2nd part:-
Dist2 = D - 20
S2 = 1.25M = 5M/4
T2 = (D-20)/(5M/4)
Hence Time(Monday) = Tm = T1 + T2 = 20/M + 4(D-20)/5M = (100 + 4(D-20))/5M

>Tuesday:
Dist = D
S = M
Time(Tuesday) = Tt = D/M
Tm:Tt = D(100 + 4(D-20))/5

i) M = 48
No info about D. Hence insufficient.
ii)D = 40. Hence sufficient to get Tm:Tt.
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Joined: 02 Oct 2017
Posts: 735
Re: Distance between Smith's house and office is D km. On Monday, S  [#permalink]

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12 Apr 2018, 19:37
Solution

As per question
Ratio of time

( (20/M) + (D-20)/1.25M )/ (D/M)

M cancel out .. only D is required to find value.
And B

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Re: Distance between Smith's house and office is D km. On Monday, S &nbs [#permalink] 12 Apr 2018, 19:37
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