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 Q50  V31
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Re: Does the point of intersection of line y=Kx+ B and line [#permalink]
Is there any typo error?

I think the second equation should be X= KY + B...

if so then 1 is sufficent, hence answer is A

On solving both the equation we will have X = -B((K^2 + 1)/(K^2 - 1))

and Y = B[1- (K^2 +1)/(K^2-1)], since both K and B are greater than 0, X and Y will be negative coordinate. If K=1, K^2 - 1 = 0 and hence X will have infinite negative value. So Case 2 can be ignored.

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Re: Does the point of intersection of line y=Kx+ B and line [#permalink]
bmwhype2 wrote:
bmwhype2 wrote:
Does the point of intersection of line y=Kx+ B and line x=KY+B have a negative coordinate?

1. k > 0, b>0
2. k > 1


Please walk me thru the answer. thanks


sorry.


Actually, if there is no error and the 2nd graph is vertical line, then the answer is C.

Let's see :

Functions are : y = kx+b, x = b/(1-k)

1 is not sufficient because if b and k both positive then :

y = kx + b passes I, III, IV quadrants.
x = b/(1-k) when k 1 then it is vertical to the left of Y and the intersection will be in either quadrant III or IV and 1 or 2 coordinates will be negative.

2 is not sufficient because it gives us obviousely not enough information.

Thus the unswer is C



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Re: Does the point of intersection of line y=Kx+ B and line [#permalink]
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