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I`d say statement 1 is sufficient. After 10 sweeps, the remainder of 90 degrees must put the line somewhere in the II quandrant. Even if r = 1~89 degrees, it doesn`t matter.

I`d say statement 1 is sufficient. After 10 sweeps, the remainder of 90 degrees must put the line somewhere in the II quandrant. Even if r = 1~89 degrees, it doesn`t matter.

(A)

GMATT73,

I'm not entirely sure I agree with you (you can correct me if I'm wrong!), you are making your calculation purely by looking at the diagram and disregarding the instructions. If I were to have a circle and was not allowed to infer from it, then I would certainly need the position of the sweep, or the angle (r) which would tell me which quadrant I am in. Let me put it this way - what if the diagram of the circle that is shown, is rotated w.r.t it's frame of reference? you have no way of knowing it, right?

So my question is - can you make a conclusion of a DS question by "inferring" from the diagram and ignoring an option? or am I overanalyzing this whole thing? I think the answer should be (c), you need both.

I remember having read somewhere that the figure can be taken as accurate, unless specifically mentioned otherwise...

A, in that case.
_________________

Uh uh. I know what you're thinking. "Is the answer A, B, C, D or E?" Well to tell you the truth in all this excitement I kinda lost track myself. But you've gotta ask yourself one question: "Do I feel lucky?" Well, do ya, punk?

it makes sense that we donot know the value of r as it could be anything from 0< to <90. but i believe it is not 0 or 90 since it is clear that the line isnot either on x axis or on y axis. if we assume r is 0, we can also assume that r is on any quadrant.

therefore after a run of 3690 degree, it should be on Qd iv.

I believe it is not drawn to scale in PS questions and in DS it is to scale unless otherwise stated. I am not 100% on this but it would agree with A being the OA.

I was leaning towards C since you dont know what R is and it could be anything, thinking its not drawn to scale.

I don't get this question. The answer A is based on the assumption that the diagram is accurate. We are not given the current position, if we were the ans would clearly be A.

The stem says that the figure above shows the current position of .... That means to me that we can be sure that it lies in the first quandrant. However, without information about r we cannot measure r in the figure and assume it is "accurate".
_________________

Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.

Yes you are right. Though I'm not sure how the axises are attibuted. Are they counted as being in one of the quandrants? In other words, I'm not sure if r could be exactly 0 or 90. Although this does not really matter, for whatever the rule is, it will be consistent. In other words if it lies in first quandrant, 90 degrees later it will be in the second quandrant, no matter what exact r is.
_________________

Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.

Yes you are right. Though I'm not sure how the axises are attibuted. Are they counted as being in one of the quandrants? In other words, I'm not sure if r could be exactly 0 or 90. Although this does not really matter, for whatever the rule is, it will be consistent. In other words if it lies in first quandrant, 90 degrees later it will be in the second quandrant, no matter what exact r is.

thank you honghu.

so far so good. was busy with lots of works and out of internet. therefore, i have been out of touch with you wonderful guys. however when i had time, i had always been reading you guys. now i am moved to the capital and so i will be regular in the forum. i took once but could not able to cross the nervus 7xx. i want to give a shot one more time. lets see what happens?

how about you? are you in simon? i believe, yes. am i right?