Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jun 0308:30 AM PDT
-09:30 AM PDT
In Episode 7 of our GMAT Ninja CR series, we are rounding up the oddballs, the misfits, and the format-benders: EXCEPT, Fill-In-The-Blanks, and other unusual Critical Reasoning question types. When you see a question that ends with a literal blank line
May 2910:00 AM IST
-11:00 PM IST
Start your journey with a fully customized action plan and work with a dedicated mentor to achieve a 735+ score.- Jun 04
08:30 AM PDT
-09:30 AM PDT
For most test takers, Data Insights is the most challenging section on the GMAT, with test takers scoring several points lower on average on DI than on Quant or Verbal and completing the section with less time to spare. - Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
Marcab
Joined: 03 Feb 2011
Last visit: 22 Jan 2021
Posts: 840
Own Kudos:
Given Kudos: 221
Status:Retaking after 7 years
Location: United States (NY)
Concentration: Finance, Economics
Schools: Simon '15 (M$)
GMAT 1: 720 Q49 V39
GPA: 3.75
21 Aug 2011, 10:25
Kudos
Bookmarks
is (k+1)(k+2)(k+3) divisible by 4?
a)k is divisible by 8
b)(k+1)/3 is odd
i dnt have any problem in statement 1 but in case of statement 2, i am confused b/w two ways.
one is-
if (k+1)/3 is odd, it means k+1 is odd...furthermore k is even
since even numbers comprises of 0 also, therefore the statement is insufficient
the second is-
k=2, (k+1)/3=(2+1)/3=1 which is odd
k=8, (k+1)/3=(8+1)/3=3 which is odd
and so on...considering this method, we can deduce k as either of {2, 8, 14, 20, 26...} for which the above expression is satisfied....
plz help
a)k is divisible by 8
b)(k+1)/3 is odd
i dnt have any problem in statement 1 but in case of statement 2, i am confused b/w two ways.
one is-
if (k+1)/3 is odd, it means k+1 is odd...furthermore k is even
since even numbers comprises of 0 also, therefore the statement is insufficient
the second is-
k=2, (k+1)/3=(2+1)/3=1 which is odd
k=8, (k+1)/3=(8+1)/3=3 which is odd
and so on...considering this method, we can deduce k as either of {2, 8, 14, 20, 26...} for which the above expression is satisfied....
plz help
Archived Topic
Hi there,
Archived GMAT Club Tests question - no more replies possible.
Where to now? Try our up-to-date Free Adaptive GMAT Club Tests
for the latest questions.
Still interested? Check out the "Best Topics" block below for better discussion and related questions.
Thank you for understanding, and happy exploring!
21 Aug 2011, 10:46
Kudos
Bookmarks
K+1/3 is odd ,
Take for instance K+1 = 9 , hence k+1/3 is odd (3) but k=8, hence 9*10*11 is NOT divisible by 4.
but if K+1=15 , k will be 14 and 15*16*17 is divisible by 4 . Hence 2 different answers , NOT sufficient.
Take for instance K+1 = 9 , hence k+1/3 is odd (3) but k=8, hence 9*10*11 is NOT divisible by 4.
but if K+1=15 , k will be 14 and 15*16*17 is divisible by 4 . Hence 2 different answers , NOT sufficient.
Marcab
Joined: 03 Feb 2011
Last visit: 22 Jan 2021
Posts: 840
Own Kudos:
Given Kudos: 221
Status:Retaking after 7 years
Location: United States (NY)
Concentration: Finance, Economics
Schools: Simon '15 (M$)
GMAT 1: 720 Q49 V39
GPA: 3.75
21 Aug 2011, 10:50
Kudos
Bookmarks
thnx man...came to knw where i was missing
Archived Topic
Hi there,
Archived GMAT Club Tests question - no more replies possible.
Where to now? Try our up-to-date Free Adaptive GMAT Club Tests
for the latest questions.
Still interested? Check out the "Best Topics" block above for better discussion and related questions.
Thank you for understanding, and happy exploring!
