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Re: Each writer for the local newspaper is paid as follows: a dollars for [#permalink]
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Bunuel wrote:
Each writer for the local newspaper is paid as follows: a dollars for each of the first n stories each month, and a + b dollars for each story thereafter, where a > b. How many more dollars will a writer who submits n + a stories in a month earn than a writer who submits n + b stories?

A. (a – b)( a + b + n)
B. a – b
C. a^2 – b^2
D. n( a – b)
E. an + bn – an


Money earned by a writer who submits n + a stories in a month

a*n + (a+b)*a

Money earned by a writer who submits n + b stories in a month

a*n + (a+b)*b

Difference in their earnings = [a*n + (a+b)*a] - [a*n + (a+b)*b] = (a+b)(a-b) = a^2 - b^2

Answer: option C
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Re: Each writer for the local newspaper is paid as follows: a dollars for [#permalink]
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Bunuel wrote:
Each writer for the local newspaper is paid as follows: a dollars for each of the first n stories each month, and a + b dollars for each story thereafter, where a > b. How many more dollars will a writer who submits n + a stories in a month earn than a writer who submits n + b stories?

A. (a – b)( a + b + n)
B. a – b
C. a^2 – b^2
D. n( a – b)
E. an + bn – an


We will calculate the earnings of the writers separately.

The writer who writes n + a stories:

For the first n stories, the writer makes a dollars each, earning na dollars in total. For the remaining (n + a) - n = a stories, the writer makes a + b dollars each, earning a(a + b) dollars in total. Thus, for the n + a stories, this writer makes na + a(a + b) dollars.

The writer who writes n + b stories:

Similar to the previous case, this writer makes na dollars for the first n stories. For the remaining (n + b) - n = b stories, which earn a + b dollars each, this writer makes b(a + b) dollars. In total, the writer makes na + b(a + b) dollars.

Now that we have the earnings of each writer, we simply need to determine the difference between the two.

na + a(a + b) - [na + b(a + b)]

na + a(a + b) - na - b(a + b)

a(a + b) - b(a + b)

(a - b)(a + b) = a^2 - b^2

The writer who writes n + a stories makes a^2 - b^2 dollars more than the writer who writes n + b stories.

Answer: C
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Each writer for the local newspaper is paid as follows: a dollars for [#permalink]
Bunuel wrote:
Each writer for the local newspaper is paid as follows: a dollars for each of the first n stories each month, and a + b dollars for each story thereafter, where a > b. How many more dollars will a writer who submits n + a stories in a month earn than a writer who submits n + b stories?

A. (a – b)( a + b + n)
B. a – b
C. a^2 – b^2
D. n( a – b)
E. an + bn – an


My approach to solving is as below:
We know that for n stories both will earn the same amount. Thus our focus is on the remaining part i.e. a stories of the first writer and b stories of the second writer
Lets call the writer who sumbits n+a stories as X and the writer who sumbits n+b stories as Y
Y's earnings: a*(a+b)=a^2+ab
X's earnings: b*(a+b)=b^2+ab
How many more dollars=difference=a^2+ab-b^2-ab=a^2-b^2
Hence option C is the ans
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Re: Each writer for the local newspaper is paid as follows: a dollars for [#permalink]
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Re: Each writer for the local newspaper is paid as follows: a dollars for [#permalink]
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