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30 Jan 2004, 20:17
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Find 'c' in the equation 3x^2 + 2x - c = 0 if the difference of the squares of the root is 20/9.
a.-8
b.8
c.-2
d.2
e.rather be :sex
a.-8
b.8
c.-2
d.2
e.rather be :sex
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30 Jan 2004, 20:24
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E) I am getting -25/9
30 Jan 2004, 20:27
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|k| = abs. value of k
Let m and n be the roots
m+n = -2/3
| m^2 - n^2 | = 20/9
|m-n| =(20/9)(3/2) = 10/3
(m+n)^2 minus (m-n)^2 = 4mn = -4c/3 = -32/3
c = 8
Let m and n be the roots
m+n = -2/3
| m^2 - n^2 | = 20/9
|m-n| =(20/9)(3/2) = 10/3
(m+n)^2 minus (m-n)^2 = 4mn = -4c/3 = -32/3
c = 8
