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For a certain set of n numbers, where n > 1, is the average (arithmeti
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26 Feb 2014, 02:24
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For a certain set of n numbers, where n > 1, is the average (arithmetic mean) equal to the median? (1) If the n numbers in the set are listed in increasing order, then the difference between any pair of successive numbers in the set is 2. (2) The range of the n numbers in the set is 2(n 1). The Official Guide For GMAT® Quantitative Review, 2ND Edition
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Re: For a certain set of n numbers, where n > 1, is the average (arithmeti
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26 Feb 2014, 02:24
SOLUTIONFor a certain set of n numbers, where n > 1, is the average (arithmetic mean) equal to the median?(1) If the n numbers in the set are listed in increasing order, then the difference between any pair of successive numbers in the set is 2. This implies that the set is even;y spaced. In any evenly spaced set the mean (average) is equal to the median. Sufficient. (2) The range of the n numbers in the set is 2(n 1). This is completely useless. Not sufficient. Answer: A. P.S. The range is the difference between the smallest and largest elements of the set.
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Re: For a certain set of n numbers, where n > 1, is the average (arithmeti
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26 Feb 2014, 04:22
For a certain set of n numbers, where n > 1, is the average (arithmetic mean) equal to the median? (1) If the n numbers in the set are listed in increasing order, then the difference between any pair of successive numbers in the set is 2. (2) The range of the n numbers in the set is 2(n 1). Sol: St 1: The above statement basically means that the terms in the set are in Arithmetic Progression and thus Mean=Median. Note that if it is given that Mean=Median then it does not mean that the set is in order St 2: The range of n numbers is 2(n1) Consider n=3 Then trange =4 Now if Set consists of elements 1,3 and 5 then Mean=Median but set consists of 1,4,5 then Mean is not equal to Median Ans is A 650 levl is okay
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Re: For a certain set of n numbers, where n > 1, is the average (arithmeti
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27 Feb 2014, 07:15
A) x4,x2,x,x+2,x+4 (condition is successive difference is 2) average = (x4+x+4)/2 = 2x/2 = x median = x
x4,x2,x,x+2,x+4,x+6 (condition is successive difference is 2) average = (x4+x+6)/2 = (2x+2)/2 = 2(x+1)/2 = x+1 median = x+1
SUFFICENT
B) What is a range? largest number  smallest number. It doesn't tell us much about the mean or median. You can try some numbers here. Constraint here is n > 1 which means you can take only 2 or 3 nos and find their average and that should be sufficient to answer the question.
INSUFFICIENT Answer A
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Re: For a certain set of n numbers, where n > 1, is the average
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15 May 2014, 11:50
ugimba wrote: For a certain set of n numbers, where n > 1, is the average (arithmetic mean) equal to the median?
(1) If the n numbers in the set are listed in increasing order, then the difference between any pair of successive numbers in the set is 2. (2) The range of n numbers in the set is 2(n  1). I thought that 2(n1) was the range for both n consecutive even/odd integers Therefore, we still have an evenly spaced set Thus, 2 was sufficient Could someone please advice where am I going wrong here? Thanks! Cheers J



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Re: For a certain set of n numbers, where n > 1, is the average
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16 May 2014, 02:26
jlgdr wrote: ugimba wrote: For a certain set of n numbers, where n > 1, is the average (arithmetic mean) equal to the median?
(1) If the n numbers in the set are listed in increasing order, then the difference between any pair of successive numbers in the set is 2. (2) The range of n numbers in the set is 2(n  1). I thought that 2(n1) was the range for both n consecutive even/odd integers Therefore, we still have an evenly spaced set Thus, 2 was sufficient Could someone please advice where am I going wrong here? Thanks! Cheers J But the reverse is not necessarily true: not all nelement sets which have the range equal to 2(n  1) are consecutive odd or consecutive even integers. For example, {2, 3, 6} has the range equal to 2(n  1) but this set is not of that type.
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Re: For a certain set of n numbers, where n > 1, is the average (arithmeti
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13 May 2016, 05:29
If numbers are listed in increasing order (consecutive even numbers, consecutive odd numbers and consecutive multiples), median=mean. Hence, since the condition 1) is always yes, the condition is sufficient. The correct answer choice is A. l For cases where we need 3 more equations, such as original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 80% chance that E is the answer (especially about 90% of 2 by 2 questions where there are more than 3 variables), while C has 15% chance. These two are the majority. In case of common mistake type 3,4, the answer may be from A, B or D but there is only 5% chance. Since E is most likely to be the answer using 1) and 2) separately according to DS definition (It saves us time). Obviously there may be cases where the answer is A, B, C or D.
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Re: For a certain set of n numbers, where n > 1, is the average (arithmeti
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28 Jan 2017, 14:56
A neat little trick to remember is that for any series that is an Arithmetic progression, namely difference between each successive term is constant, the median is always = mean. I'll try to prove it below. Let us say there are n terms. There are two pssibillities n is odd or n is even. Let us say the constant difference is d (2 in the case of this problem). 1st term: a, 2nd term = a+d, 3rd term = a+2*d .... nth term = a+(n1)*d Adding all you get Sum = a*n +[ (1+2+3...+(n1))]*d = a*n +[ n*(n1)/2]*d ( another interesting result sum of the first n1 integers is n*(n1)/2]. Hence the Average = Sum/n = a+(n1)/2*d n is odd: Median = (n+1)/2 th term = a+(n1)/2*d = Average so if n is odd we have proved avg always equal to mean. n is even: Median = average of n/2 and (n/2+1)th term =[ a+(n/21)*d+a+(n/2)*d ]/2 = a+(n1)*d/2 = Average so if n is even too we have proved avg always equal to mean. Thus (1) is always sufficient to answer such questions of if avg = median. (2) Since only range is given we cant determine anything about the numbers in between so this informatino is insufficient. Hence answer is A.
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