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20 Apr 2020, 11:30
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For all real numbers a, b, c, d, e, and f, the operation Θ is defined by the equation \((a, b, c) Θ (d, e, f) = ad + be + cf\). What is the value of \((1,−2, 3) Θ (1, −\frac{1}{2}, \frac{1}{3})\) ?
A. -1
B. 5/6
C. 1
D. 5/2
E. 3
PS37631.02
A. -1
B. 5/6
C. 1
D. 5/2
E. 3
PS37631.02
20 Apr 2020, 11:35
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\((1,−2, 3) Θ (1, −\frac{1}{2}, \frac{1}{3})\)
= \([1*1] + [(-2)*(\frac{-1}{2})] + [3*\frac{1}{3}]\)
= 1+1+1
=3
= \([1*1] + [(-2)*(\frac{-1}{2})] + [3*\frac{1}{3}]\)
= 1+1+1
=3
gmatt1476
For all real numbers a, b, c, d, e, and f, the operation Θ is defined by the equation \((a, b, c) Θ (d, e, f) = ad + be + cf\). What is the value of \((1,−2, 3) Θ (1, −\frac{1}{2}, \frac{1}{3})\) ?
A. -1
B. 5/6
C. 1
D. 5/2
E. 3
PS37631.02
A. -1
B. 5/6
C. 1
D. 5/2
E. 3
PS37631.02
MBABackstage
Joined: 13 Apr 2020
Last visit: 24 Jul 2020
Posts: 16
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Schools: LBS '16 (A$)
20 Apr 2020, 11:35
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Answer = (1 x 1) + (-2 * - 1/2) + (3 * 1/3)
= 1 + 1 + 1
= 3
(E)
= 1 + 1 + 1
= 3
(E)
