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For all x and y, (4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ?

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For all x and y, (4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ?  [#permalink]

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New post Updated on: 26 May 2017, 12:08
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A
B
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E

Difficulty:

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Question Stats:

82% (00:56) correct 18% (00:58) wrong based on 99 sessions

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For all x and y, \((4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ?\)

(A) \(–4x^2 – 18xy – 16y^2\)

(B) \(–4x^2 + 6xy – 16y^2\)

(C) \(–4x^2 + 6xy – 8y^2\)

(D) \(4x^2 – 6xy + 16y^2\)

(E) \(12x^2 – 18xy – 8y^2\)

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Originally posted by Kritesh on 26 May 2017, 12:04.
Last edited by Bunuel on 26 May 2017, 12:08, edited 1 time in total.
Formatted the question.
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Re: For all x and y, (4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ?  [#permalink]

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New post 26 May 2017, 13:43
\((4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 )\)

= \((4x^2 - 8x^2) + (– 6xy + 12xy) + (– 12y^2 - 4y^2 )\)

= \(–4x^2 + 6xy – 16y^2\)(Option B)
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Re: For all x and y, (4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ?  [#permalink]

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New post 26 May 2017, 13:59
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Kritesh wrote:
For all x and y, \((4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2) = ?\)

(A) \(–4x^2 – 18xy – 16y^2\)

(B) \(–4x^2 + 6xy – 16y^2\)

(C) \(–4x^2 + 6xy – 8y^2\)

(D) \(4x^2 – 6xy + 16y^2\)

(E) \(12x^2 – 18xy – 8y^2\)


This is all about collecting like terms

(4x² – 6xy – 12y²) – (8x² – 12xy + 4y²) = ??

4x² - 8x² = -4x²
–6xy - (–12xy) = 6xy (aka +6xy)
–12y² - 4y² = -16y²

So, (4x² – 6xy – 12y²) – (8x² – 12xy + 4y²) = -4x² + 6xy -16y²


Answer:

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Re: For all x and y, (4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ?  [#permalink]

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New post 01 Jun 2017, 09:48
Kritesh wrote:
For all x and y, \((4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ?\)

(A) \(–4x^2 – 18xy – 16y^2\)

(B) \(–4x^2 + 6xy – 16y^2\)

(C) \(–4x^2 + 6xy – 8y^2\)

(D) \(4x^2 – 6xy + 16y^2\)

(E) \(12x^2 – 18xy – 8y^2\)


4^x - 6xy - 12y^2 - (8x^2 - 12xy + 4y^2)

4^x - 6xy - 12y^2 - 8x^2 + 12xy - 4y^2

-4x^2 + 6xy - 16y^2

Answer: B
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Re: For all x and y, (4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ?  [#permalink]

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New post 21 Jul 2018, 11:58
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Re: For all x and y, (4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ? &nbs [#permalink] 21 Jul 2018, 11:58
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