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# For integers a and b, (a^3-a^2-b)^1/2=7, a=? 1). a^2-a=12

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Joined: 08 Aug 2005
Posts: 251
For integers a and b, (a^3-a^2-b)^1/2=7, a=? 1). a^2-a=12 [#permalink]

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23 Nov 2005, 23:44
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For integers a and b, (a^3-a^2-b)^1/2=7, a=?
1). a^2-a=12
2). b^2-b=2

OA is B
SVP
Joined: 24 Sep 2005
Posts: 1885

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24 Nov 2005, 00:52
24 Nov 2005, 00:52
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# For integers a and b, (a^3-a^2-b)^1/2=7, a=? 1). a^2-a=12

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