|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Updated on: 20 Aug 2013, 02:07
Originally posted by vinayparamanand on 19 Aug 2013, 20:13.
Last edited by Bunuel on 20 Aug 2013, 02:07, edited 1 time in total.
Last edited by Bunuel on 20 Aug 2013, 02:07, edited 1 time in total.
Renamed the topic and edited the question.
Kudos
Bookmarks
N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
50% (02:16) correct
50%
(03:32)
wrong
based on 38
sessions
History
Date
Time
Result
Not Attempted Yet
Four friends Laura, Nancy, James and Simon buy some pencils, pens and erasers from a shop. Laura buys 5 pencils, 6 pens, and 1 eraser for $17.50. Nancy buts 3 pens, 3 pencils, and 2 erasers for $ 10. James buys 5 pens, 2 pencils, and 5 erasers for $14.50. How much will Simon have to pay if he buys 3 pens, 2 pencils, and 5 erasers?
Note: How often in the GMAT do such questions appear?
Can i have a generic way to solve such questions?
OA:
Note: How often in the GMAT do such questions appear?
Can i have a generic way to solve such questions?
OA:
$9.5
20 Aug 2013, 01:14
Kudos
Bookmarks
vinayparamanand
Let the cost of a pencil be $x
Let the cost of a pen be $y
Let the cost of a erasers be $z
Now,
for Laura 5x+6y+z = 17.50 ----a
for Nancy 3x+3y+2z=10 ----b
for James 2x+5y+5z=14.50 ---c
We have to find value for Simon i.e 3x+2y+5z=??
Now,
2b - a => x + 3z = 2.5 ----d
5b - 3c => 9x - 5z = 6.5 ------e
Solving, d and e
9d - e => 9x + 27z - (9x-5z ) = 22.5 - 6.5
32z = 16
z = 1/2
putting z in d, we get x = 1
putting z and x in a we get y= 2
3x + 2y +5z = 3 + 4 + 2.5 => 9.5$
Thanks,
Jai
KUDOS if it HELPED..!!!
01 Sep 2013, 11:56
Kudos
Bookmarks
I agree with the solution provided here, but I would like to know an alternative way that is easier and can be done in the shortest amount of time possible. The current approach is lengthy and time-consuming.
Thanks.
Thanks.
jaituteja
