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Fourninths of a drink mix is dye and the rest is sugar. Whe
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25 Dec 2010, 05:26
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67% (02:23) correct 33% (02:44) wrong based on 387 sessions
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Fourninths of a drink mix is dye and the rest is sugar. When the mix is added to water a gallon of drink is made that is 7.5% sugar. What percentage of the gallon is dye? (A) 6 (B) 6.5 (C) 7.5 (D) 8 (E) 24
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Re: Mixture problem
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25 Dec 2010, 06:47
The proportion of Dye and sugar will remain constant.
Dye/Sugar = (4/9)/(5/9) = x/7.5 => 4/5 = x/7.5 => x = 4*7.5/5 = 6.
Answer is A.




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Re: Mixture problem
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25 Dec 2010, 06:49
I use a very simple way with fractions to find the calue of x:
\(\frac{4}{9}/\frac{x}{100} = \frac{5}{9}/\frac{7,5}{100}\)
When you solve it you will find that x=6



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Re: Mixture problem
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25 Dec 2010, 07:41
Can some one explain when to use traditional mixture solutions using grid and when to use simple proportionality equations?
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Re: Mixture problem
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25 Dec 2010, 16:20
rg1 wrote: Can some one explain when to use traditional mixture solutions using grid and when to use simple proportionality equations? Here you are adding the whole mixture to water, also the ratio water to sugar remains unchanged. Also you only have to make simple comptutation: 7,5/5*4=6
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Re: Fourninths of a drink mix is dye and the rest is sugar. Whe
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16 Dec 2013, 04:42
rxs0005 wrote: Fourninths of a drink mix is dye and the rest is sugar. When the mix is added to water a gallon of drink is made that is 7.5% sugar. What percentage of the gallon is dye?
(A) 6 (B) 6.5 (C) 7.5 (D) 8 (E) 24 Here, let's say that the gallon is 100 litres. Then sugar in the gallon will be 7.5 litres Now 5/9x=7.5 'x' is the amoung of the mix poured into gallon x = (9)(1.5) Now dye will be 9(1.5)*(4/9)=1.5*4=6 Hence A Even if you don't find the way to solve it you can straight eliminate answers C,D,E cause the amount of dye is always going to be less given the 4:5 ratio Hope it helps Cheers! J



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Re: Fourninths of a drink mix is dye and the rest is sugar. Whe
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14 Jan 2015, 19:57
In the drink mix, if \(\frac{4}{9} =\) dye, then sugar \(= 1  \frac{4}{9} = \frac{5}{9}\) If sugar constitutes \(\frac{7.5}{100}\), then dye percentage \(= \frac{7.5}{100} * \frac{4}{9} * \frac{9}{5} = \frac{6}{100} = 6%\) Answer = A
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Fourninths of a drink mix is dye and the rest is sugar. When the mix
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28 Jan 2017, 11:49
Bunuel wrote: Fourninths of a drink mix is dye and the rest is sugar. When the mix is added to water a gallon of drink is made that is 7.5% sugar. What percentage of the gallon is dye?
A. 6 B. 6.5 C. 7.5 D. 8 E. 24 ratio of sugar in mix to sugar in gallon=(5/9)/.075 ratio of dye in mix to dye in gallon=(4/9)/x (5/9)/(.075)=(4/9)/x x=6/100=6% A



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Re: Fourninths of a drink mix is dye and the rest is sugar. When the mix
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29 Jan 2017, 01:38
Bunuel wrote: Fourninths of a drink mix is dye and the rest is sugar. When the mix is added to water a gallon of drink is made that is 7.5% sugar. What percentage of the gallon is dye?
A. 6 B. 6.5 C. 7.5 D. 8 E. 24 suppose it is a litre instead of gallon (As 1 litre =1000 ml) 7.5 % of a litre of solution is sugar 75ml is sugar Now 75 ml sugar constitutes 5/9 of initial mixture means 55.55% of initial mixture means initial mixture is 134 ml thus dye is ~45%(ie 4/9) of 134 ml thus 60 ml so 60ml is 6% of 1000ml ie 1Litre Ans A



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Re: Fourninths of a drink mix is dye and the rest is sugar. When the mix
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29 Jan 2017, 08:38
Is answer A ? Let x be volume of dye. sugar is 5/9x. 5/9x = 7.5/100.
x= 27/200. dye % = 4/9 * 27/200 *100 = 6%



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Re: Fourninths of a drink mix is dye and the rest is sugar. When the mix
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29 Jan 2017, 10:47
Bunuel wrote: Fourninths of a drink mix is dye and the rest is sugar. When the mix is added to water a gallon of drink is made that is 7.5% sugar. What percentage of the gallon is dye?
A. 6 B. 6.5 C. 7.5 D. 8 E. 24 A is the answer. 4/9 is dye , 5/9 sugar 5/9 represent 7.5 % 4/9 represent X (4/9*7.5)/5/9 6 we will get....



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Re: Fourninths of a drink mix is dye and the rest is sugar. When the mix
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07 May 2017, 13:40
Let initial amount be 9. so dye equals 4 parts and sugar equals 5 parts.
now, 5 parts is 7.5% of the total. let total amount now be = a. thus 7.5/100 a = 5. a = 500/7.5
we need sugar / total sugar hasn't changed so : 4/a = 4/ (500/7.5) = 0.06. thus 6%



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Fourninths of a drink mix is dye and the rest is sugar. Whe
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29 Oct 2017, 11:02
Say, Dye = 4, Sugar=5 We can find the equation below: 5= (9+water) *.075 Water= 57.66 Now,percentage of dye is: 5/(57.66+9) = .06 Or 6%
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Re: Fourninths of a drink mix is dye and the rest is sugar. Whe
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31 Oct 2017, 15:42
rxs0005 wrote: Fourninths of a drink mix is dye and the rest is sugar. When the mix is added to water a gallon of drink is made that is 7.5% sugar. What percentage of the gallon is dye?
(A) 6 (B) 6.5 (C) 7.5 (D) 8 (E) 24 Since 4/9 of the drink mix is dye, 5/9 of the mix is sugar. We can create the following proportion in which n = the percentage of dye: (4/9)/(5/9) = n/(7.5/100) 4/5 = 100n/7.5 500n = 30 n = 30/500 = 6/100 = 6% Answer: A
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Re: Fourninths of a drink mix is dye and the rest is sugar. Whe
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21 Nov 2017, 04:07
rxs0005 wrote: Fourninths of a drink mix is dye and the rest is sugar. When the mix is added to water a gallon of drink is made that is 7.5% sugar. What percentage of the gallon is dye?
(A) 6 (B) 6.5 (C) 7.5 (D) 8 (E) 24 Responding to a pm: Quote: is it possible to apply scale method to this one..?
You have 3 elements here  dye, sugar and water. So we cannot use the scale method. We see that sugar is 5/9 of the drink and 7.5% of the entire water solution. Dye which is 4/9 of the drink would be (7.5/5)*4 = 6% of the entire water solution Answer (A)
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Re: Fourninths of a drink mix is dye and the rest is sugar. Whe
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21 Nov 2017, 04:19
(4/9)/(5/9) = x/7.5 => 4/5 = x/7.5 => x = 4*7.5/5 = 6. So answer should be A
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Re: Fourninths of a drink mix is dye and the rest is sugar. Whe
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26 Feb 2018, 02:34
rxs0005 wrote: Fourninths of a drink mix is dye and the rest is sugar. When the mix is added to water a gallon of drink is made that is 7.5% sugar. What percentage of the gallon is dye?
(A) 6 (B) 6.5 (C) 7.5 (D) 8 (E) 24 Let X be the total vol of mix Dye = 4/9*X Sugar = 5/9*X [color=#ffff00]Volume of sugar and dye remain unchanged
Therefore conc of Sugar in final mix = total sugar/1 gallon = 7.5% ( Given)[/color] = (5/9*x)/1 = 7.5 =5X= 67.5 ===> x = 13.5 Hence dye percentage = 4/9*13.5 = 6 Answer A 6




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