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# geometry helppppp

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Intern
Joined: 06 Oct 2011
Posts: 10

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08 Aug 2012, 14:07
In the figure below, if AC=12, DC=18, and DB=15, what is the length of AF?

A)8
B)9
C)10
D)11
E)12

Figure reference: http://24.media.tumblr.com/tumblr_m8gfp ... 1_1280.jpg

Kudos [?]: 6 [0], given: 2

Senior Manager
Joined: 15 Jun 2010
Posts: 359

Kudos [?]: 440 [0], given: 50

Schools: IE'14, ISB'14, Kellogg'15
WE 1: 7 Yrs in Automobile (Commercial Vehicle industry)

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08 Aug 2012, 15:11
No able to view the link.
Kindly post the question as per rule with OA and in right forum.
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Kudos [?]: 440 [0], given: 50

Manager
Joined: 01 Mar 2009
Posts: 192

Kudos [?]: 45 [0], given: 23

Location: United States
Concentration: Strategy, Technology
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08 Aug 2012, 15:41

I thought this was a very difficult problem. I stared at this for a while before figuring it out. Make point X the point where DB and AF intersect. The angles of the four sided figure in the middle (BCFX), add up to 360. If there are two 90 degree angles, then the remaining angles, FXB and FCB, add up to 180. You will also note that angles FXB and FXD also add up to 180 as well as angles FXB and AXB.

FXB + FCB = 180
FXB + FXD = 180
FXB + AXB = 180

Therefore, Angles FCB, FXD, and AXB are all equal. Lets call their value Y for now. Now you have 3 triangles-- AXB, DXF, AFC, and DBC-- that all have angles that are 90 and Y degrees. They all have the same 3rd angle, which we can call Z for now. We do not need to know the value of Y or Z.

Now, from the above configuration lets extract 2 triangles: CFA and CBD. We can find their proportionality be comparing known values on proportional sides. Since we have values for both CA and CD and they proportional, lets use them. CB:CD = (12):(18) = 2:3. Therefore, the ratio of the sides of triangle CFA to CBD is 2:3. Now lets find AF. Since AF and BD are proportional at 2:3 and BD = 15, then AF = 15(2/3) = 30/3 = 10

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Veritas Prep GMAT Instructor
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09 Aug 2012, 04:40
arifaisal wrote:
In the figure below, if AC=12, DC=18, and DB=15, what is the length of AF?

A)8
B)9
C)10
D)11
E)12

Figure reference: http://24.media.tumblr.com/tumblr_m8gfp ... 1_1280.jpg

Such figures should immediately remind you of similar triangles. The two triangles FCA and BCD have a right angle each and a common angle (angle A) each. Hence, their third corresponding angles would also be equal to each other. By AA rule, the triangles are similar.
Therefore, the ratio of their corresponding sides will be equal.

CA/CD = FA/BD
12/18 = FA/15
FA = 10

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Kudos [?]: 16936 [0], given: 230

Re: geometry helppppp   [#permalink] 09 Aug 2012, 04:40
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