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Given that there are 5 basketball players per team, how many ways can

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Given that there are 5 basketball players per team, how many ways can  [#permalink]

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New post 02 Jun 2016, 04:37
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Given that there are 5 basketball players per team, how many ways can you select 2 basketball players from 3 teams if no more than one player can be selected from each team?

(A) 15
(B) 30
(C) 60
(D) 75
(E) 90

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Re: Given that there are 5 basketball players per team, how many ways can  [#permalink]

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New post 02 Jun 2016, 04:44
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Bunuel wrote:
Given that there are 5 basketball players per team, how many ways can you select 2 basketball players from 3 teams if no more than one player can be selected from each team?

(A) 15
(B) 30
(C) 60
(D) 75
(E) 90


First select 2 group out of available 3 groups. This cane be done in 3C2 ways = 3 ways

Now from each group we have to select one person only: 5C1 * 5C1= 5 * 5 = 25

Total ways: 25 * 3 = 75 ways.

Answer D.
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Re: Given that there are 5 basketball players per team, how many ways can  [#permalink]

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New post 02 Jun 2016, 06:29
Bunuel wrote:
Given that there are 5 basketball players per team, how many ways can you select 2 basketball players from 3 teams if no more than one player can be selected from each team?

(A) 15
(B) 30
(C) 60
(D) 75
(E) 90


ways to select 2 out of 3= 3

ways to select 1 player from 2 teams= 5*5

Total ways to select 1 player from 2 teams out of 3= 5*5*3= 75

D should be the answer
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Re: Given that there are 5 basketball players per team, how many ways can  [#permalink]

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New post 05 Aug 2016, 14:27
2 teams can be selected from 3 teams in 3C2 ways = 3 ways
as the condition is that the 2 players should be from different teams
one player can be chosen from 1st team in 5 ways
similarly another player can be chosen from 2nd team in 5 ways
Total number of ways to choose the player = 5 * 5 * 3 = 75 ways
Correct Answer - D
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Re: Given that there are 5 basketball players per team, how many ways can  [#permalink]

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New post 05 Aug 2016, 17:39
Hi All,

If you're not comfortable with the traditional math approach to this question, you can still use 'brute force' to get to the answer rather easily.

Since we have 3 teams of 5 players each, I'm going to refer to the 3 teams of players as...

12345
ABCDE
VWXYZ

We're told that we have to pick 2 players and that we CANNOT pick them from the SAME team.

Each of the players from 12345 can be paired up with any of the players from ABCDE or VWXYZ. That's a total of 10 options per player from 12345...

(10)(5) = 50 options

Next, we can consider ABCDE. Since each of those players has already been paired up with each of the players on 12345, we don't have to consider those options. We just have to consider pairing each of the players on ABCDE with each of the players on VWXYZ. That's 5 players with 5 different pairings each:

(5)(5) = 25 additional options.

Finally, all of the players from VWXYZ have already been paired up with all of the players from 12345 and ABCDE, so there's no other options left.

50 + 25 = 75 total options

Final Answer:

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Re: Given that there are 5 basketball players per team, how many ways can  [#permalink]

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New post 05 Aug 2016, 23:27
5*5 + 5*5 + 5*5 answer 75

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Re: Given that there are 5 basketball players per team, how many ways can  [#permalink]

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Re: Given that there are 5 basketball players per team, how many ways can &nbs [#permalink] 04 Jul 2018, 23:44
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