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jimmyjamesdonkey
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GMATPrep DS! Number Properties 29 Dec 2007, 13:45
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Is |x| > |y|?

1) x^2 > y^2

2) x > y
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Mia.Andersson
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GMATPrep DS! Number Properties 29 Dec 2007, 19:13
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A

1. Sufficient.
For all 4 positive and negative combinations of X and Y.

2. Not Sufficient.
e.g. X=-1 and Y=-2
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Mia.Andersson
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GMATPrep DS! Number Properties 29 Dec 2007, 19:15
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By the way, you posted the question in the wrong section i guess.
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Manbehindthecurtain
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GMATPrep DS! Number Properties 10 Jan 2008, 18:58
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How A?

What are the four positive and negative combinations? if x^2 and y^2 = x,-x and y,-y; I was thinking 1) says..
x>y : Yes to |x|>|y|
x>-y : Yes/No : (x = 100, -y = -2)/(x = 1, -y = -2)
-x>-y, ie: -1>-2, but |-1| is not > |-2|...

What am I missing about the combinations?


Mia.Andersson
A

1. Sufficient.
For all 4 positive and negative combinations of X and Y.

2. Not Sufficient.
e.g. X=-1 and Y=-2
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GMATBLACKBELT
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GMATPrep DS! Number Properties 10 Jan 2008, 19:45
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Manbehindthecurtain
How A?

What are the four positive and negative combinations? if x^2 and y^2 = x,-x and y,-y; I was thinking 1) says..
x>y : Yes to |x|>|y|
x>-y : Yes/No : (x = 100, -y = -2)/(x = 1, -y = -2)
-x>-y, ie: -1>-2, but |-1| is not > |-2|...

What am I missing about the combinations?


Mia.Andersson
A

1. Sufficient.
For all 4 positive and negative combinations of X and Y.

2. Not Sufficient.
e.g. X=-1 and Y=-2
Show more


|x| is essentially x^2 in terms of sign that is.

Essentially anything to the ^2 power is going to be positive or 0.

In S1: X and Y cannot be 0 b/c x^2>y^2 we cant have 0>0. And we can't have only one equal to zero either because the negative will become positive. Also note that since x^2 (positive number when solved) > y^2 (positive number when solved) |x|>|y| this has to be true.

Suff.


S2: take x=-1 and y=-2 x>y but |x|>|y|?? of course not. you can imagine several values for the opposite though.
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