Last visit was: 26 Apr 2024, 11:21 It is currently 26 Apr 2024, 11:21

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Math Expert
Joined: 02 Sep 2009
Posts: 92948
Own Kudos [?]: 619218 [2]
Given Kudos: 81609
Send PM
Manager
Manager
Joined: 12 Nov 2016
Posts: 60
Own Kudos [?]: 41 [0]
Given Kudos: 469
Send PM
Senior Manager
Senior Manager
Joined: 21 Mar 2016
Posts: 448
Own Kudos [?]: 117 [0]
Given Kudos: 103
Send PM
Intern
Intern
Joined: 03 Dec 2016
Posts: 32
Own Kudos [?]: 16 [0]
Given Kudos: 728
Send PM
Re: Grass on a lawn grows everyday by a fixed percent of the height on the [#permalink]
Bunuel wrote:
Grass on a lawn grows everyday by a fixed percent of the height on the previous day. However, cows graze and reduce the height of the grass by 1 mm every day. What was the height of the grass on the first day before the cows started grazing? Assume that the cows graze at the end of the day, after which the grass grows in the beginning of the next day.

(1) The grass grows every day by 2 percent of the height on the previous day.
(2) The grass is completely grazed in 3 days.


Assume growth everyday is x% and initial height is H

(1) X = 2. But this statement does not say anything about the height on any particular day. NOT SUFFICIENT

(2) H(1+x)^3 - 3(1) =0. NOT SUFFICIENT as no information on H and x provided

(1) + (2) . x = 2. Hence, H(1+2%)^3 - 3(1) =0. Solvable and Sufficient

Hence C
Intern
Intern
Joined: 16 Apr 2017
Posts: 35
Own Kudos [?]: 138 [1]
Given Kudos: 82
Send PM
Re: Grass on a lawn grows everyday by a fixed percent of the height on the [#permalink]
1
Kudos
Bunuel wrote:
Grass on a lawn grows everyday by a fixed percent of the height on the previous day. However, cows graze and reduce the height of the grass by 1 mm every day. What was the height of the grass on the first day before the cows started grazing? Assume that the cows graze at the end of the day, after which the grass grows in the beginning of the next day.

(1) The grass grows every day by 2 percent of the height on the previous day.
(2) The grass is completely grazed in 3 days.


Let initial height be h
Acc to 1===> then at the end of third day after grazing the height would be H(final) = [[[1.2h -1]*1.2 - 1]*1.2 - 1], but we do not know the final height H(final) so we cannot determine h, insufficient
Acc to 2====> We do not know how much does the percent the height increases daily.

Combined we know H(final) =0 ==> [[[1.2h -1]*1.2 - 1]*1.2 - 1] =0, and we can determine h.....sufficient
GMAT Club Bot
Re: Grass on a lawn grows everyday by a fixed percent of the height on the [#permalink]
Moderator:
Math Expert
92947 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne