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Hoses A, B, and C pump a swimming pool full of water. Hoses A and B [#permalink]

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14 Oct 2017, 00:28

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47% (01:35) wrong based on 59 sessions

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Hoses A, B, and C pump a swimming pool full of water. Hoses A and B working simultaneously can pump the pool full of water in 4 hours, and Pumps B and C working simultaneously can pump the pool full of water in 6 hours. How long does it take pump A working alone to fill the pool?

(1) All three hoses working simultaneously can fill the pool in 3 hours and 36 minutes.

(2) Hose A and Hose C working simultaneously can fill the swimming pool in twice the time it would take all three hoses together to fill the swimming pool.

Re: Hoses A, B, and C pump a swimming pool full of water. Hoses A and B [#permalink]

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14 Oct 2017, 01:08

Consider A, B, C be the individual time taken by each hose Given - 1/A + 1/B = 1/4 1/B + 1/C = 1/6

Statement 1: 1/A + 1/B + 1/C = 1/~3.5 Sufficient, to find A, if you put 1/A + 1/6 = 1/~3.5

Statement 2:1/A+1/C = 2(1/A+ 1/B+ 1/C) Which deduces to 0=1/A + 1/B+1/B+1/C and hence insufficient as we dont have value of 1/B even if we have value for 1/B + 1/C.

Hoses A, B, and C pump a swimming pool full of water. Hoses A and B working simultaneously can pump the pool full of water in 4 hours, and Pumps B and C working simultaneously can pump the pool full of water in 6 hours. How long does it take pump A working alone to fill the pool?

(1) All three hoses working simultaneously can fill the pool in 3 hours and 36 minutes.

(2) Hose A and Hose C working simultaneously can fill the swimming pool in twice the time it would take all three hoses together to fill the swimming pool.

Work completed by A and B in 1 hr=1/4 -- (i) Work completed by B and C in 1 hr=1/6 --- (ii)

Statement 1: Work completed by A, B and C in 1 hr= 1/3.6 This is sufficient because along with (i), we can find work completed by a in 1 hr as 1/3.6 -1/6

Statement 2: Work completed by A and C in 1 hr = 1/2 of A,B,C --- (iii). If we add (i) , (ii) and (iii), we will get the same info as statement 1. So sufficient

Hoses A, B, and C pump a swimming pool full of water. Hoses A and B working simultaneously can pump the pool full of water in 4 hours, and hoses B and C working simultaneously can pump the pool full of water in 6 hours. How long does it take pump A working alone to fill the pool?

(1) All three hoses working simultaneously can fill the pool in 3 hours and 36 minutes. (2) Hose A and Hose C working simultaneously can fill the swimming pool in twice the time it would take all three hoses together to fill the swimming pool.

----ASIDE---------------------------- Rule #1: If a person can complete an entire job in k hours, then in one hour, the person can complete 1/k of the job Example: If it takes Sue 5 hours to complete a job, then in one hour, she can complete 1/5 of the job. In other words, her work rate is 1/5 of the job per hour

Rule #2: If a person completes a/b of the job in one hour, then it will take b/a hours to complete the entire job Example: If Sam can complete 1/8 of the job in one hour, then it will take him 8/1 hours to complete the job. Likewise, if Joe can complete 2/3 of the job in one hour, then it will take him 3/2 hours to complete the job.

Let’s use these rules to solve the question. . . . -----------------------------------------

Target question:How long does it take pump A working alone to fill the pool?

Given: Hoses A and B working simultaneously can pump the pool full of water in 4 hours, and Pumps B and C working simultaneously can pump the pool full of water in 6 hours. Let A = the RATE at which hose A can fill the pool alone Let B = the RATE at which hose B can fill the pool alone Let C = the RATE at which hose C can fill the pool alone

Hoses A and B working simultaneously can pump the pool full of water in 4 hours From rule #1. the combined RATE of hoses A and B is 1/4 of the pool PER HOUR In other words, A + B = 1/4

B and C working simultaneously can pump the pool full of water in 6 hours. From rule #1. the combined RATE of hoses B and C is 1/6 of the pool PER HOUR In other words, B + C = 1/6

Statement 1: All three hoses working simultaneously can fill the pool in 3 hours and 36 minutes. In other words, working together hoses A, B and C can fill the pool in 3.6 hours From rule #1. the combined RATE of hoses A, B and C is 1/3.6 of the pool PER HOUR In other words, A + B + C = 1/3.6

At this point, we have the following system: A + B = 1/4 B + C = 1/6 A + B + C = 1/3.6

Since we have 3 different equations with 3 variables, we can definitely solve the system to determine the value of A. Of course, we're not going to waste our time and actually solve the system. We need only recognize that we COULD determine the value of A, which means we COULD determine the time it would take pump A working alone to fill the pool Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: Hose A and Hose C working simultaneously can fill the swimming pool in twice the time it would take all three hoses together to fill the swimming pool. This tells us that the combined RATE of hoses A and C is HALF the combined RATE of hoses A, B and C So, we can write: A + C = 0.5(A + B + C)

At this point, we have the following system: A + B = 1/4 B + C = 1/6 A + C = 0.5(A + B + C)

Once again, we have 3 different equations with 3 variables, which means we can definitely solve the system to determine the value of A. So, we COULD determine the time it would take pump A working alone to fill the pool Since we can answer the target question with certainty, statement 2 is SUFFICIENT