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13 Dec 2016, 06:49
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
90% (01:19) correct
10%
(01:20)
wrong
based on 183
sessions
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How many different ways are there to arrange a group of 3 adults and 4 children in 7 seats if adults must have the first, third, and 7 seats?
A. 12
B. 144
C. 288
D. 1,400
E. 5,040
A. 12
B. 144
C. 288
D. 1,400
E. 5,040
13 Dec 2016, 07:56
Kudos
Bookmarks
There are 3 adults that should be seated on three particular seats and 4 children on the rest four. Adults and children cannot switch places with each other, only among themselves
Hence: \(3!*4! = 6*24 = 144\)
Answer B
Hence: \(3!*4! = 6*24 = 144\)
Answer B
10 Dec 2017, 07:04
Kudos
Bookmarks
the adults have to be in 1 3 and 7th place , therefore : A*c*A*c*c*c*A
so it will be 3 x C x 2 x C x C x C x 1
now the children taking remaining places will be
3 x 4 x 2 x 3 x 2 x 1 x 1 = 144
so it will be 3 x C x 2 x C x C x C x 1
now the children taking remaining places will be
3 x 4 x 2 x 3 x 2 x 1 x 1 = 144
