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# How many odd numbers with 4 different digits, can be formed using the

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Intern
Joined: 30 Mar 2015
Posts: 15
GMAT 1: 730 Q49 V40
How many odd numbers with 4 different digits, can be formed using the [#permalink]

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05 Apr 2015, 11:30
1
1
00:00

Difficulty:

25% (medium)

Question Stats:

74% (01:15) correct 26% (01:27) wrong based on 98 sessions

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How many odd numbers with 4 different digits, can be formed using the digits 1,2,3,4,5,6,7,8?

A. 71

B. 200

C. 210

D. 840

E.1680
Intern
Joined: 29 Dec 2014
Posts: 25
Concentration: Operations, Strategy
GMAT 1: 690 Q48 V35
GMAT 2: 710 Q48 V39
Re: How many odd numbers with 4 different digits, can be formed using the [#permalink]

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05 Apr 2015, 12:01
1
hi petu

i solved it like this:

first: with four different digits you can make a four digit integer. since 0 is not available 3 digit integers are not applicable.
let the number be _ _ _ _
second: odd numbers end with 1, 3 , 5 or 7 hence for the last digit slot only 4 numbers to choose from the available 8. since repetition is not allowed ..the rest of the slots can be filled in 7 ,6 ,5 ways whichever way you wish to fill ( starting from thousands place & moving right to tens place or vice-versa it is the same because of no-repeat condition)
Thus, the required arrangement can happen in (7*6*5)*4 or (5*6*7)*4 either of which yields 840 ways. ans:D
Director
Joined: 12 Nov 2016
Posts: 776
Location: United States
Schools: Yale '18
GMAT 1: 650 Q43 V37
GRE 1: 315 Q157 V158
GPA: 2.66
Re: How many odd numbers with 4 different digits, can be formed using the [#permalink]

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23 Sep 2017, 22:35
petu wrote:
How many odd numbers with 4 different digits, can be formed using the digits 1,2,3,4,5,6,7,8?

A. 71

B. 200

C. 210

D. 840

E.1680

7*6*5*4 = 840

D
Re: How many odd numbers with 4 different digits, can be formed using the   [#permalink] 23 Sep 2017, 22:35
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# How many odd numbers with 4 different digits, can be formed using the

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