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thanks a lot .... this solution cleared my doubt.
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Also here: m25-76554.html

See this post for a listing of all discussions: gmat-club-tests-master-threads-all-tests-78599.html
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Thank you for explanation. It is very helpful!
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How many odd three-digit integers greater than 800 are there such that all their digits are different?
A. 40
B. 60
C. 72
D. 81
E. 104

In the range 800 - 900:
1 choice for the first digit: 8;
5 choices for the third digit: 1, 3, 5, 7, 9;
8 choices for the second digit: 10 digits - first digit - third digit = 8 digits.

1*5*8 = 40.

In the range 900 - 999:
1 choice for the first digit: 9;
4 choices for the third digit: 1, 3, 5, 7 (9 is out as it's first digit);
8 choices for the second digit: 10 digits - first digit - third digit = 8 digits.

1*4*8 = 32.

Total: 40+32 = 72.

Answer: C.

Also discussed at: odd-3-digit-integers-94655.html and no-properties-71853.html?hilit=range%20choice%20first%20digit

Hope it helps.
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