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  • Typical Day of a UCLA MBA Student - Recording of Webinar with UCLA Adcom and Student

     December 14, 2018

     December 14, 2018

     10:00 PM PST

     11:00 PM PST

    Carolyn and Brett - nicely explained what is the typical day of a UCLA student. I am posting below recording of the webinar for those who could't attend this session.
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     December 15, 2018

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How to Find the Solutions of?

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Intern
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How to Find the Solutions of?  [#permalink]

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New post 03 Mar 2018, 07:01
Can someone help me with the process to find the solution to:
\(\frac{(x+2)(x+3)}{(x-2)} >=0\)

The result I have is \(x>2, x<-3, -3<=x<=-2\) and \(-2<x<2\)
I am able to understand the first two solutions but not the last two.

Any inputs would be appreciated. Thanks.
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Re: How to Find the Solutions of?  [#permalink]

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New post 04 Mar 2018, 07:42
the last one is not possible

sub any value to test

for eg: x=0

you get a neg value
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Re: How to Find the Solutions of?  [#permalink]

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New post 08 Mar 2018, 12:08
Pritishd wrote:
Can someone help me with the process to find the solution to:
\(\frac{(x+2)(x+3)}{(x-2)} >=0\)

The result I have is \(x>2, x<-3, -3<=x<=-2\) and \(-2<x<2\)
I am able to understand the first two solutions but not the last two.

Any inputs would be appreciated. Thanks.


This is really a positive/negative problem, not an algebra problem. You know that because it tells you something is greater than (or equal to) 0. Whenever you see that on the GMAT, you want to translate it in your head as 'is positive'.

Okay, so (x+2)(x+3)/(x-2) is positive (or zero). What does that mean?

When a fraction is positive, then either the top and bottom are both positive, or the top and bottom are both negative.

So, top and bottom are both positive. (x+2)(x+3) is positive, and (x-2) is also positive. When does that happen? Only when x>2. Otherwise, x-2 would come out negative.

Other case: top and bottom are both negative. (x+2)(x+3) is negative, and (x-2) is also negative. That's tricky. If x-2 is negative, then x<2. But when is (x+2)(x+3) negative? Only when one of those terms is negative, and the other one is positive. That only happens when x is between -2 and -3. So our second scenario happens when x<2, and also -3<=x<=-2. However, we don't have to say 'x<2', because if x is between -3 and -2, you already know that it's less than 2. So that's redundant info.

So we've got two solutions: in the case where top and bottom are both positive, x>2.

In the case where top and bottom are both negative, -3 <= x <= -2.

Try plugging some numbers in there to check!
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Re: How to Find the Solutions of? &nbs [#permalink] 08 Mar 2018, 12:08
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