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# How to Find the Solutions of?

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Intern
Joined: 18 Jul 2015
Posts: 18
GMAT 1: 530 Q43 V20
WE: Analyst (Consumer Products)
How to Find the Solutions of?  [#permalink]

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03 Mar 2018, 07:01
Can someone help me with the process to find the solution to:
$$\frac{(x+2)(x+3)}{(x-2)} >=0$$

The result I have is $$x>2, x<-3, -3<=x<=-2$$ and $$-2<x<2$$
I am able to understand the first two solutions but not the last two.

Any inputs would be appreciated. Thanks.
Intern
Joined: 04 Jan 2018
Posts: 37
Re: How to Find the Solutions of?  [#permalink]

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04 Mar 2018, 07:42
the last one is not possible

sub any value to test

for eg: x=0

you get a neg value
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Joined: 04 Dec 2015
Posts: 649
GMAT 1: 790 Q51 V49
GRE 1: Q170 V170
Re: How to Find the Solutions of?  [#permalink]

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08 Mar 2018, 12:08
Pritishd wrote:
Can someone help me with the process to find the solution to:
$$\frac{(x+2)(x+3)}{(x-2)} >=0$$

The result I have is $$x>2, x<-3, -3<=x<=-2$$ and $$-2<x<2$$
I am able to understand the first two solutions but not the last two.

Any inputs would be appreciated. Thanks.

This is really a positive/negative problem, not an algebra problem. You know that because it tells you something is greater than (or equal to) 0. Whenever you see that on the GMAT, you want to translate it in your head as 'is positive'.

Okay, so (x+2)(x+3)/(x-2) is positive (or zero). What does that mean?

When a fraction is positive, then either the top and bottom are both positive, or the top and bottom are both negative.

So, top and bottom are both positive. (x+2)(x+3) is positive, and (x-2) is also positive. When does that happen? Only when x>2. Otherwise, x-2 would come out negative.

Other case: top and bottom are both negative. (x+2)(x+3) is negative, and (x-2) is also negative. That's tricky. If x-2 is negative, then x<2. But when is (x+2)(x+3) negative? Only when one of those terms is negative, and the other one is positive. That only happens when x is between -2 and -3. So our second scenario happens when x<2, and also -3<=x<=-2. However, we don't have to say 'x<2', because if x is between -3 and -2, you already know that it's less than 2. So that's redundant info.

So we've got two solutions: in the case where top and bottom are both positive, x>2.

In the case where top and bottom are both negative, -3 <= x <= -2.

Try plugging some numbers in there to check!
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Re: How to Find the Solutions of? &nbs [#permalink] 08 Mar 2018, 12:08
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