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06 Dec 2016, 09:36
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
89% (01:20) correct
11%
(02:20)
wrong
based on 110
sessions
History
Date
Time
Result
Not Attempted Yet
If 119 of the 200 children in a school like juice with their breakfast, 113 like milk and 51 like to have both, how many like neither juice nor milk?
A. 83
B. 70
C. 51
D. 32
E. 19
A. 83
B. 70
C. 51
D. 32
E. 19
06 Dec 2016, 10:43
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Bunuel
If 119 of the 200 children in a school like juice with their breakfast, 113 like milk and 51 like to have both, how many like neither juice nor milk?
A. 83
B. 70
C. 51
D. 32
E. 19
\(n (J) = 119\)A. 83
B. 70
C. 51
D. 32
E. 19
\(n (M) = 113\)
\(n ( M ∩ J ) = 51\)
\(n ( M ∪ J ) = n (J) + n (M) - n ( M ∩ J )\)
\(n ( M ∪ J ) = 119 + 113 - 51\)
\(n ( M ∪ J ) = 181\)
\(n ( M ∪ J )' = Σ - n ( M ∪ J )\)
\(n ( M ∪ J )' = 200 - 181\)
So, \(n ( M ∪ J )' = 19\)
Hence, Answer will be (E) 19
08 Dec 2016, 10:24
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Option E)
Total no. of students = 200
No. of students who like Juice = 119
No. of students who like Milk = 113
No. of students who like Both = 51
Total no. of students = No. of students who like only Juice + No. of students who like only Milk + No. of students who like Both + No. of students who like Neither
200 = (119 - 51) + (113 - 51) + 51 + No. of students who like Neither
No. of students who like Neither = 200 - 68 - 62 - 51 = 19
Total no. of students = 200
No. of students who like Juice = 119
No. of students who like Milk = 113
No. of students who like Both = 51
Total no. of students = No. of students who like only Juice + No. of students who like only Milk + No. of students who like Both + No. of students who like Neither
200 = (119 - 51) + (113 - 51) + 51 + No. of students who like Neither
No. of students who like Neither = 200 - 68 - 62 - 51 = 19
