BrentGMATPrepNow wrote:
If |2x + 1| < 3x - 2, then which of the following represents all possible values of x ?
(A) -3 < x < 0.2
(B) x > -3
(C) x < -3
(D) 0.2 < x < 3
(E) x > 3
STRATEGY: Students who fail to recognize the differences between high school math and GMAT math will attempt to solve the given inequality and then look for their answer among the answer choices (here's an article about high school math vs GMAT math: https://gmatclub.com/forum/gmat-math-vs ... 88210.html).
The much faster (and less prone to errors) GMAT math approach is to test values.
Let's first test whether
x = 0 is a solution to the given inequality by plugging it in to get: |2(0) + 1| < 3(0) - 2
Simplify to get: |1| < -2, which simplifies further to get 1 < -2
Since the resulting inequality is NOT TRUE, we know that
x = 0 is NOT a solution, which means we can eliminate any answer choices that says
x = 0 IS a solution.
So, we can eliminate A and B
Now let's test another value. How about
x = 10.
Plug it in to get: |2(10) + 1| < 3(10) - 2
Simplify to get: |21| < 28, which simplifies further to get 21 < 28
Since the resulting inequality is TRUE, we know that
x = 10 IS a solution, which means we can eliminate any answer choices that says
x = 10 is NOT a solution.
So, we can eliminate C and D
By the process of elimination,
the correct answer is E