Hi All,

This Roman Numeral question can be solved with a mix of Algebra and TESTing VALUES. Also notice that the three Roman Numerals have the SAME fraction on the "left side" - this means that you don't have to do calculations 3 times, you just have to do them ONCE and put them in all 3 Roman Numerals.

We're told that A, B, C and D are all POSITIVE and that A/B < C/D. We're asked which to the Roman Numerators MUST be true (which is the same as saying "which of these is ALWAYS TRUE no matter how many different examples you try?").

Since the variables are all POSITIVE, we can cross-multiply the inequality...

A/B < C/D

AD < BC

It's also worth noting that this inequality has a couple of great "weak spots": You can make the A, B and D the same value and make the C really BIG. You can also make the A, C and D the same value and make the B really BIG.

With those ideas in mind, I'm going to TEST VALUES.

IF....

A = C = D = 1

B = 100

(A+C)/(B+D) = 2/101

I. Is 2/101 < C/D = 1/1?

The answer is YES

This is NOT enough proof to say that this is ALWAYS TRUE though....

II. Is 2/101 < A/B = 1/100?

The answer is NO

ELIMINATE Roman Numeral II. Eliminate Answers C and D.

III. Is 2/101 = A/B + C/D = 1/100 + 1/1?

The answer is NO

ELIMINATE Roman Numeral III. Eliminate Answer E.

We're now down to just Roman Numeral I. Notice how it has the came fraction (C/D) as the inequality from the prompt. That is INTERESTING. Let's see what happens when we cross-multiply the inequality in Roman Numeral I.....

(A+C)/(B+D) < C/D

D(A+C) < C(B+D)

AD + CD < BC + CD

The "CD"s cancel...

AD < BC

This is what we PROVED early on in the work. Roman Numeral I MUST be TRUE.

Final Answer:

GMAT assassins aren't born, they're made,

Rich

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