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Re: If a dice is thrown 4 times, what is the probability that an odd numbe [#permalink]
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Given that a dice is thrown 4 times and We need to find what is the probability that an odd number will come up exactly 3 times ?

As we are rolling a dice four times => Number of cases = \(6^4\) = 1296

Now lets pick the three times out of four when dice will land in an odd number. This can be done in 4C3 ways
=> \(\frac{4!}{3!*(4-3)!}\) = \(\frac{4*3!}{3!*1!}\) = 4 ways

Now, these three dice can get any of the three odd numbers (1, 3, 5) in 3*3*3 ways
The fourth dice can get any of the three even numbers (2, 4, 5) in 3 ways

=> Total number of cases = 4 * 3 * 3 * 3 * 3

=> Probability that an odd number will come up exactly 3 time = \(\frac{4 * 3 * 3 * 3 * 3}{6^4}\) = \(\frac{1}{4}\)

So, Answer will be C
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

GMAT Club Bot
Re: If a dice is thrown 4 times, what is the probability that an odd numbe [#permalink]
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