Bunuel
Bunuel
If \(a\) is a positive integer, \(k\) and \(m\) are integers, and \(k > m\), is \(a^k > a^m\) ?
(1) \(a^k < 1\)
(2) \(a^m < 1\)
a is a positive integer, k and m are integers. If k>m, is a^k>a^m?
(1) a^k<1
(2) a^m<1
Bumping!!! Knockout this one and get KUDOS for a correct solution!!!
If \(a\) is a positive integer, \(k\) and \(m\) are integers, and \(k > m\),
\(a^k\) will always be greater than \(a^m\) unless \(a=1\)Thus if we can somehow prove that \(a≠1\), we can answer this question.
Statement 1: \(a^k < 1\)
Had \(a\) been equal to \(1\), \(a^k\) would be equal to \(1\). But since \(a^k\) is less than \(1\), clearly \(a≠1\)
Statement 2: \(a^m < 1\)
Had \(a\) been equal to \(1\), \(a^m\) would be equal to \(1\). But since \(a^m\) is less than \(1\), clearly \(a≠1\)
Using both the statements individually we can say that \(a≠1\) and since we know that \(a\) is a positive integer and \(k\) and \(m\) are integers such that \(k>m\), \(a^k\) will always be greater than \(a^m\). Hence, option D.Posted from my mobile device