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# If a is the average of the first 5 positive multiples of 5 and M is th

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If a is the average of the first 5 positive multiples of 5 and M is th  [#permalink]

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27 Dec 2016, 09:06
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If a is the average of the first 5 positive multiples of 5 and M is the mode of the set of numbers {2, 3, 2, 3, 2, 5, 2, 3, 5, 3, 5, 3, 5, 5, 5, 2, 5, 5} what is the value of a – M?

A. 5
B. 7
C. 10
D. 11
E. 13

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Re: If a is the average of the first 5 positive multiples of 5 and M is th  [#permalink]

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28 Dec 2016, 06:59
ANS - C

a=15
M=5

a-M=10
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Re: If a is the average of the first 5 positive multiples of 5 and M is th  [#permalink]

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28 Dec 2016, 09:34
Bunuel wrote:
If a is the average of the first 5 positive multiples of 5 and M is the mode of the set of numbers {2, 3, 2, 3, 2, 5, 2, 3, 5, 3, 5, 3, 5, 5, 5, 2, 5, 5} what is the value of a – M?

A. 5
B. 7
C. 10
D. 11
E. 13

Let the first 5 positive multiples of 5 be { 5 , 10 , 15 , 20 , 25 }

$$a = \frac{5 + 10 + 15 + 20 + 25}{5}$$

Or, $$a = 15$$

In the set {2, 3, 2, 3, 2, 5, 2, 3, 5, 3, 5, 3, 5, 5, 5, 2, 5, 5} we have

5 two's
5 three's
7 five's

The mode of a data set is the number that occurs most frequently in the set, so mode of the above set will be 5..

Or, M = 5

Hence, $$a – M = 15 - 5 = 10$$

Thus, the correct answer will be (C) 10
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Re: If a is the average of the first 5 positive multiples of 5 and M is th  [#permalink]

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06 Aug 2018, 04:49
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Re: If a is the average of the first 5 positive multiples of 5 and M is th   [#permalink] 06 Aug 2018, 04:49
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# If a is the average of the first 5 positive multiples of 5 and M is th

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