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If a motorist had driven 1 hour longer on a certain day and

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Manager
Joined: 12 Mar 2003
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If a motorist had driven 1 hour longer on a certain day and [#permalink]

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22 Apr 2003, 18:14
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If a motorist had driven 1 hour longer on a certain day and at an average rate of 5 miles per hour faster, he would have covered 70 more miles than he actually did. How many more miles would he have covered than he actually did if he had driven 2 hours longer and at an average rate of 10 miles per hour faster on that day?

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Intern
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Re:HOW TO SOLVE [#permalink]

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30 May 2003, 22:26
I think if you have some choice, guessing will be more faster than computing.

i have 2 ways.

1. supposed the number t= 5 v= 20
5*20 = 100
6*25 = 150 Diff 50
7*30 = 210 Diff 50*2 + 10

based on the calculation above, the answer for this proplem will be
70*2 +10

2. compute by using equation. S=vt

(t+1)(v+5) = S +70

vt + 5t + v + 5 = S+70

5t + V = 65 -------- (1)

2 * (1) = 10t + 2V = 130

(t+2)(v+10) = vt + 10t + 2v +20

= S + 130 +20

= S+150

Thus, the answer is 150

if anyone has more faster way, please tell me.

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Manager
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30 May 2003, 23:35
For every one hour he drove 5 miles farther.....and he drove 1 hr longer......therefore he drove for (70-5)/5 = 13hrs

the five is subtracted for the 1 hr longer that he drove

so if he had travelled at 10 more miles per hour he would have travelled 13*10 + 2*10 = 150 miles

hope it makes sense

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Joined: 30 Oct 2003
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28 Jan 2004, 14:39
It is even simpler.

He travelled 70 more miles in one extra hour. SO he must have travelled 70 miles in 1 hr making his speed 70 mi/hr. This is 5 more miles/hr than original speed. So his original speed is 65 mi/hr. Adding 10 to this makes it 75 mi/hr. 75 mi/hr for 2 hrs = 150 miles

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Senior Manager
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30 Jan 2004, 17:57
Guys, correct me if I am wrong but the question asks for "How many more miles would he have covered than he actually did" The bold part is important.

With the given information the driver will drive 150 miles more than the usual . But only 80 miles more than the distance he drove on that specific day.

Does any one agree?

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Senior Manager
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01 Feb 2004, 12:58
gmatblast wrote:
Guys, correct me if I am wrong but the question asks for "How many more miles would he have covered than he actually did" The bold part is important.

With the given information the driver will drive 150 miles more than the usual . But only 80 miles more than the distance he drove on that specific day.

Does any one agree?

Has anybody had chance to look at this? Thanks

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SVP
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01 Feb 2004, 14:01
I dont know how to explain it well. See if you can figure it out

His average speed = V on a regular day he travels X miles for T hours
so X = VT
One fine day he travelled T+1 hours at V+5 miles per hour
(T+1)*(V+5) = X+70 On this day he travelled 70 miles extra as he drove 1 hour extra.
VT+V+5T+5 = X+70 and since X = VT we have V+5T = 65
On some day he travels T+2 hours at V+10 mph
(T+2)*(V+10) = Y miles
VT+2V+10T+20 = Y
We need to find Y-X =Y-VT miles
Y-VT = 2V+10T+20 but V+5T = 65 so
Y-VT = 2*65+20 = 150

I think you are considering those two hours as daily part of his travel. I believ you have to compare it with how much he travels at V mph for T hours.

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Intern
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02 Feb 2004, 21:55
anandnk wrote:
It is even simpler.

He travelled 70 more miles in one extra hour. SO he must have travelled 70 miles in 1 hr making his speed 70 mi/hr. This is 5 more miles/hr than original speed. So his original speed is 65 mi/hr. Adding 10 to this makes it 75 mi/hr. 75 mi/hr for 2 hrs = 150 miles

Yes, this is the simplest way to do this one. thanks Anandnk, this is good!

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CEO
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30 Nov 2007, 06:41
gmatfordays wrote:
anandnk wrote:
It is even simpler.

He travelled 70 more miles in one extra hour. SO he must have travelled 70 miles in 1 hr making his speed 70 mi/hr. This is 5 more miles/hr than original speed. So his original speed is 65 mi/hr. Adding 10 to this makes it 75 mi/hr. 75 mi/hr for 2 hrs = 150 miles

Yes, this is the simplest way to do this one. thanks Anandnk, this is good!

Kudos [?]: 1076 [0], given: 4

30 Nov 2007, 06:41
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If a motorist had driven 1 hour longer on a certain day and

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