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If a square's side is increased from 5 units long to 6 units long, whi

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If a square's side is increased from 5 units long to 6 units long, whi [#permalink]

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New post 25 Dec 2017, 23:22
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If a square's side is increased from 5 units long to 6 units long, which of the following is the percent by which the area is increased?

A. 1%
B. 4%
C. 11%
D. 36%
E. 44%
[Reveal] Spoiler: OA

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Re: If a square's side is increased from 5 units long to 6 units long, whi [#permalink]

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New post 26 Dec 2017, 00:59
Bunuel wrote:
If a square's side is increased from 5 units long to 6 units long, which of the following is the percent by which the area is increased?

A. 1%
B. 4%
C. 11%
D. 36%
E. 44%


As this is a very simple cacluation, we'll just do it.
This is a Precise approach.

We're asked to calculate (increase from 5^2 to 6^2)/(area of 5^2)
This is (6^2 - 5^2)/5^2 = (36 - 25)/25 = 11/25 = 44/100 = 44%
(E) is our answer.
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If a square's side is increased from 5 units long to 6 units long, whi [#permalink]

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New post 26 Dec 2017, 01:21
Bunuel wrote:
If a square's side is increased from 5 units long to 6 units long, which of the following is the percent by which the area is increased?

A. 1%
B. 4%
C. 11%
D. 36%
E. 44%



Current Area= 5*5= 25
New Area= 6*6=36

% Change= (New Area- Current Area)/(Current Area)*100 = \(((36-25)/36)*100= (11/25)*100= 44\)%. Hence E.
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Re: If a square's side is increased from 5 units long to 6 units long, whi [#permalink]

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New post 26 Dec 2017, 17:00
Bunuel wrote:
If a square's side is increased from 5 units long to 6 units long, which of the following is the percent by which the area is increased?

A. 1%
B. 4%
C. 11%
D. 36%
E. 44%



Area of a square: \(side^2\)

Square with side 5, has an area of: \(side^2=5^2=25\)
Square with side 6, has an area of: \(side^2=6^2=36\)

Percentage change: \(\frac{After-Before}{Before}=\frac{36-25}{25}=\frac{11}{25}=0.44\)=44%.

(E) is the answer.
Re: If a square's side is increased from 5 units long to 6 units long, whi   [#permalink] 26 Dec 2017, 17:00
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