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If Frederick is riding his bicycle at m meters per t minutes, how far

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If Frederick is riding his bicycle at m meters per t minutes, how far [#permalink]

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New post 28 Apr 2017, 02:23
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If Frederick is riding his bicycle at m meters per t minutes, how far does he travel in d days, in terms of d, m, and t?

A. 60*24*md/t
B. 60*24*t/(md)
C. md/(60*24*t)
D. t/(60*24*md)
E. md/t
[Reveal] Spoiler: OA

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Re: If Frederick is riding his bicycle at m meters per t minutes, how far [#permalink]

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New post 28 Apr 2017, 02:58
If Fredrick travels m meters in t minutes, the distance he would travel in d days is
d * 24(number of hours in a day) * 60(number of minutes in an hour) * m(meters)/t(minutes)
(Option A)

Another method(Plugging numbers)
Consider if he travels 5 meters in 10 minutes.
He would travel 30 meters in 60 minutes(1 hours) and in an entire day he would travel 720 meters.
Only Option A will give you the answer, provided you put d=1, m=5 and t = 10
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Re: If Frederick is riding his bicycle at m meters per t minutes, how far [#permalink]

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New post 28 Apr 2017, 05:51
Distance = speed * time
=(m/t)*d*24*60 time is derived by using days 1 day = 24 hr and 1 hr = 60 mins
Distance travelled = 60*24md/t
Option A
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Re: If Frederick is riding his bicycle at m meters per t minutes, how far [#permalink]

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New post 02 May 2017, 03:33
stem says,,, m metres in t mins,,,
in one min dist travelled will be (m/t)

hence total distance in one day is 60*24*(m/t)*d

ans A
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Re: If Frederick is riding his bicycle at m meters per t minutes, how far [#permalink]

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New post 02 May 2017, 15:52
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Bunuel wrote:
If Frederick is riding his bicycle at m meters per t minutes, how far does he travel in d days, in terms of d, m, and t?

A. 60*24*md/t
B. 60*24*t/(md)
C. md/(60*24*t)
D. t/(60*24*md)
E. md/t


We are given that Frederick is riding his bicycle at m meters per t minutes. Thus, his rate is m/t meters/minute.

Since we need to determine how far he travels in d days, let’s convert days to minutes:

1 day = 24 hours

1 hour = 60 minutes

Thus, 1 day = 60 x 24 minutes.

So d days = d x 60 x 24 minutes.

Since rate x time = distance, Frederick can travel (m/t)(d x 60 x 24) = (60 x 24 x md)/t meters.

Answer: A
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Re: If Frederick is riding his bicycle at m meters per t minutes, how far   [#permalink] 02 May 2017, 15:52
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