flower07 wrote:

(A) 1

(B) 23/7

(C) 7/23

(D) -4

(e) -2

I do not understand this basic and I need clarification on this question...

G raised to the power of 2 < G

=> G raised to the power of 2 -G < 0

=> G(G-1) < 0

=> Either G < 0 OR G-1 < 0

=> G < 0 or G < 1

=> G must be less than 0.

So, shouldn't the negative numbers be the possible values of G?

What I am missing, please?

Hi, the Answer is C.

For your question why negative numbers cannot be a value of G.

we have the inequality as \(G^2\)<G.

When simplified we get G<0 or G<1.

G can never be less than zero, since \(G^2\) is less than G.

If G is negative, for example G= -2 then \(G^2\) becomes 4 which contradicts the statement \(G^2\)<G.

So choose the value which is less than 1 and by POE we get \(7/23\)

Hope it helps

Also Please read the

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