flower07 wrote:
(A) 1
(B) 23/7
(C) 7/23
(D) -4
(e) -2
I do not understand this basic and I need clarification on this question...
G raised to the power of 2 < G
=> G raised to the power of 2 -G < 0
=> G(G-1) < 0
=> Either G < 0 OR G-1 < 0
=> G < 0 or G < 1
=> G must be less than 0.
So, shouldn't the negative numbers be the possible values of G?
What I am missing, please?
Hi, the Answer is C.
For your question why negative numbers cannot be a value of G.
we have the inequality as \(G^2\)<G.
When simplified we get G<0 or G<1.
G can never be less than zero, since \(G^2\) is less than G.
If G is negative, for example G= -2 then \(G^2\) becomes 4 which contradicts the statement \(G^2\)<G.
So choose the value which is less than 1 and by POE we get \(7/23\)
Hope it helps
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