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If j, k, m, n, and p are consecutive positive integers

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If j, k, m, n, and p are consecutive positive integers  [#permalink]

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New post Updated on: 07 Jun 2014, 07:14
2
7
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A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

55% (01:17) correct 45% (01:13) wrong based on 263 sessions

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I. j; k; m; n; p
II. j - 10; m; m; m; p + 15
III. j + 2; k + 1; m; n - 1; p - 2

If j, k, m, n, and p are consecutive positive integers such that j < k < m < n < p, the data sets I, II, and III above are ordered from greatest standard deviation to least standard deviation in which of the following?

(A) I, III, II
(B) II, I, III
(C) II, III, I
(D) III, I, II
(E) III, II, I

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Originally posted by Gnpth on 07 Jun 2014, 06:54.
Last edited by Bunuel on 07 Jun 2014, 07:14, edited 1 time in total.
Edited the question.
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Re: If j, k, m, n, and p are consecutive positive integers  [#permalink]

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New post 07 Jun 2014, 07:13
2
3
Gnpth wrote:
If j, k, m, n, and p are consecutive positive integers such that j < k < m < n < p, the data sets I, II, and III above are ordered from greatest standard deviation to least standard deviation in which of the following?

(A) I, III, II
(B) II, I, III
(C) II, III, I
(D) III, I, II
(E) III, II, I


I. j; k; m; n; p
II. j - 10; m; m; m; p + 15
III. j + 2; k + 1; m; n - 1; p - 2

If j, k, m, n, and p are consecutive positive integers such that j < k < m < n < p, the data sets I, II, and III above are ordered from greatest standard deviation to least standard deviation in which of the following?


(A) I, III, II
(B) II, I, III
(C) II, III, I
(D) III, I, II
(E) III, II, I

j, k, m, n, and p are consecutive positive integers such that j < k < m < n < p, thus the third set is {m, m, m, m, m}. The standard deviation of a set with all identical elements is 0 (the SD is always \(\geq{0}\)). Therefore the third set has the smallest standard deviation.

Only option B offers that.

Answer: B.

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Re: If j, k, m, n, and p are consecutive positive integers  [#permalink]

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New post 21 Aug 2014, 12:36
2
A 30sec Approach

Range of 1st Set = (p-j)
Range of 2nd Set = P+15 - j +10 = (p-j) +25
Range of 3rd Set = P -2 - j - 2 = (p-j) - 4

R2 > R1 > R3 ==> SD2 > SD1 > SD3
Since, Higher the Range -> More Dispersion in the Set -> More Standard Deviation.

Hope it helps. :)
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Re: If j, k, m, n, and p are consecutive positive integers  [#permalink]

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Re: If j, k, m, n, and p are consecutive positive integers &nbs [#permalink] 19 Oct 2018, 20:33
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