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fozzzy
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KarishmaB
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I agree with Karishma,
50+m
500+m
.
.
500000+m , when divided by 3 will give remainder 2 +m so, the value of r will depend upon m.
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My two cents :wink:
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we know that 5X10^N +m gives remainder 0 when sum of digits divisible by 3 else some value
now
statement 1 : N has some value positive but we know nothing about M so sum of digits = 5+N number of zeros+m :M unknown so insufficient
statement 2: M is 1 and N has some value positive so sum of digits = 5+N number of zeros+1=6 always therefore divisible and sufficient

B
please tell if my approach is correct
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StrugglingGmat2910
we know that 5X10^N +m gives remainder 0 when sum of digits divisible by 3 else some value
now
statement 1 : N has some value positive but we know nothing about M so sum of digits = 5+N number of zeros+m :M unknown so insufficient
statement 2: M is 1 and N has some value positive so sum of digits = 5+N number of zeros+1=6 always therefore divisible and sufficient

B
please tell if my approach is correct

Hi '

I think your approach is correct. The answer is dependent on the value of m, not n as explained in the solution above.
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Can anyone solve this using the EVI approach? Equation > Variable.
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(5*(10^n)+m)/3 can be write as
(5*((9+1)^n)+m)/3
5/3 + ((9+1)^n)/3 + m/3
5/3 --> r =2
((9+1)^n)/3 --> r = 1
total remainder = 2*1 + remainder of m/3
we only need to know what is the remainder of m/3
(1) does not provide with the information needed
(2) m=1 --> remainder of 1/3 --> r = 1. thus total remainder is 2*1 + 1 = 3 --> that means the remainder is zero
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