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Re: If n/2 is the cube of a positive integer and n/3 is the square of [#permalink]
AnujL wrote:
gmatophobia how did we determine that n is even ?


AnujL refer to this statement -

\(\frac{n}{2}\) is the cube of a positive integer.


Inference:
1) n must have a 2 in the first place for us to perform the division operation; The result of the operation \(\frac{ n}{2}\) is an integer, so n = some integer * 2
2) If n = some integer * 2, n is even.

Hope this helps !
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Re: If n/2 is the cube of a positive integer and n/3 is the square of [#permalink]
given n/2 is cube and n/3 is square
so n has to be even and should be divisible by 3
432 = sum of digits is divisible by 3
sufficient to condition as well and minimum value
432 is correct answer option B

Bunuel wrote:
If \(\frac{n}{2}\) is the cube of a positive integer and \(\frac{n}{3}\) is the square of a positive integer. What is the minimum possible value of \(n\)?

A. 423
B. 432
C. 442
D. 447
E. 532
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Re: If n/2 is the cube of a positive integer and n/3 is the square of [#permalink]
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