LM
Please explain the answer......
If n is a positive integer, and r is the remainder when 4 + 7n is divided by 3, what is the value of r?The condition "r is the remainder when 4 + 7n is divided by 3" can be expressed as \(4 + 7n = 3q + r\), where r is an integer such that \(0 \leq r < 3\). The question asks for the value of r.
(1) n + 1 is divisible by 3
This implies \(n + 1 = 3k\), or \(n = 3k - 1\). Substituting this value of n into the equation, we get \(4 + 7(3k - 1) = 3q + r\). Simplifying, this becomes \(3(7k - 1 - q) = r\). This means that r is a multiple of 3. However, since r is an integer within the range \(0 \leq r < 3\), the only possibility is r = 0. Sufficient.
(2) n > 20.
This is clearly not sufficient. For example, if \(n = 21\), then \(4 + 7n = 151\), resulting in \(r = 1\). However, if \(n = 22\), then \(4 + 7n = 158\), resulting in \(r = 2\).
Answer: A.
I am not sure if it has been asked/discussed before, but can we use the following approach:
re-write 4 + 7n as (3+1) + (6n + 1). now if we divide this by 3 we are left with (1) + (2n +1), which is essentially (2n + 2) ------> 2(n+1)/3 leaves no remainder or in other words 0 - using statement 1 information.