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Question Stats:
68% (01:32) correctHistory
We have two cases as we have |p| | |
-Case 1: p ≥ 0 => |p| = p => |p - p| = 3 => 0 = 3 => NO SOLUTION | -Case 2: p ≤ 0 => |p| = -p => |p - (-p)| = 3 => |2p| = 3 => 2*|p| = 3 => 2*-p = 3 => p = -3/2 The condition was p ≤ 0 and -3/2 ≤ 0 => p = -3/2 is a SOLUTION |