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Bunuel
­If \(|p – |p|| = 3\), how many values of \(p\) satisfy this equation?

A. 0
B. 1
C. 2
D. 3
E. 4­



­LOGICAL APPROACH
\(|p – |p|| = 3\)

Observation 1: If p were a positive value then p and |p| would be equal and p – |p| would be zero

Since, \(|p – |p|| = 3\) i.e. p MUST be negative

Observation 2: since p is Negative therefore |p| must be positive and \(|p – |p||\) mist be equal to |2p|

Now since |2p| = 3
p must be -1.5 only hence ONLY ONE SOLUTION

Answer: Option B
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Given that |p – |p|| = 3 and We need to find how many values of p satisfy this equation?

We have two cases as we have |p|
-Case 1: p ≥ 0
=> |p| = p

=> |p - p| = 3

=> 0 = 3


=> NO SOLUTION
-Case 2: p ≤ 0
=> |p| = -p
=> |p - (-p)| = 3
=> |2p| = 3
=> 2*|p| = 3
=> 2*-p = 3
=> p = -3/2
The condition was p ≤ 0 and -3/2 ≤ 0
=> p = -3/2 is a SOLUTION

So, there is one solution for p = -3/2

So, Answer will be B
Hope it helps!

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