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If Sn=(Sn-1)^{-Sn-2}, S1=1, and S2=2, then S6=?

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If Sn=(Sn-1)^{-Sn-2}, S1=1, and S2=2, then S6=?  [#permalink]

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New post 18 Oct 2018, 01:14
1
1
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

79% (02:15) correct 21% (02:09) wrong based on 69 sessions

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[Math Revolution GMAT math practice question]

If Sn=(Sn-1)^{-Sn-2}, S1=1, and S2=2, then S6=?

\(A. \frac{1}{2}\)
\(B. \frac{1}{4}\)
\(C. 2\)
\(D. 4\)
\(E. 16\)

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Re: If Sn=(Sn-1)^{-Sn-2}, S1=1, and S2=2, then S6=?  [#permalink]

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New post 18 Oct 2018, 02:32
The answer is option E. Hope the image might help.

Kudos if you like! :grin:
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Re: If Sn=(Sn-1)^{-Sn-2}, S1=1, and S2=2, then S6=?  [#permalink]

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New post 21 Oct 2018, 18:56
=>

S3=(S2)^{-S1}=(2)-1=\(\frac{1}{2}\)
S4=(S3)^{-S2}=\((\frac{1}{2})^{-2}=4\)
S5=(S4)^{-S3}=\((4)^{\frac{-1}{2}}=\frac{1}{2}\)
S6=(S5)^{-S4}=\((\frac{1}{2})^{-4}=16\)

Therefore, the answer is E.
Answer: E
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Re: If Sn=(Sn-1)^{-Sn-2}, S1=1, and S2=2, then S6=?   [#permalink] 21 Oct 2018, 18:56
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If Sn=(Sn-1)^{-Sn-2}, S1=1, and S2=2, then S6=?

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