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If the average (arithmetic mean) of p, q and r is 50 and the average

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If the average (arithmetic mean) of p, q and r is 50 and the average  [#permalink]

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New post 28 Dec 2017, 21:53
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A
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C
D
E

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Question Stats:

94% (01:09) correct 6% (01:22) wrong based on 76 sessions

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Re: If the average (arithmetic mean) of p, q and r is 50 and the average  [#permalink]

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New post 29 Dec 2017, 04:10
Bunuel wrote:
If the average (arithmetic mean) of p, q and r is 50 and the average ( arithmetic mean) of q, r and s is 60, what is the value of s – p?

A. 60
B. 50
C. 40
D. 30
E. 10


\(Average=\frac{Sum}{Terms}\)

\(\frac{(q+r+s)}{3}=60\), \(q+r+s=180\)

\(\frac{(p+q+r)}{3}=50\), \(p+q+r=150\)

\((q+r+s)-(p+q+r)=180-150\), \(s-p=30\).

(D) is the answer.
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Re: If the average (arithmetic mean) of p, q and r is 50 and the average  [#permalink]

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New post 20 Jan 2018, 23:08
(p + q + r)/3 = 50
Hence, p + q + r = 150 Equation 1

(q + r + s)/3 = 60
Hence, q + r + s = 180 Equation 2

Subtract Equation 1 from Equation 2:
(q + r + s) - (p + q + r) = 180 - 150
s - r = 30 (Answer D)
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Re: If the average (arithmetic mean) of p, q and r is 50 and the average  [#permalink]

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New post 19 Mar 2018, 09:25
Bunuel wrote:
If the average (arithmetic mean) of p, q and r is 50 and the average ( arithmetic mean) of q, r and s is 60, what is the value of s – p?

A. 60
B. 50
C. 40
D. 30
E. 10


(p + q + r)/3 = 50

(p + q + r) = 150 -------(I)

(q + r + s)/3 = 60

q +r + s = 180 -----(II)

Subtract I from II,

s - p = 30

(D)
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Re: If the average (arithmetic mean) of p, q and r is 50 and the average  [#permalink]

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New post 19 Mar 2018, 09:52
Bunuel wrote:
If the average (arithmetic mean) of p, q and r is 50 and the average ( arithmetic mean) of q, r and s is 60, what is the value of s – p?

A. 60
B. 50
C. 40
D. 30
E. 10


\(p + q + r = 150\)
\(q + r + s = 180\)

Now, \((q + r + s) - (p + q + r) = 180 - 150\)

Or, \((s - p) = 30\), Answer must be (D)
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Re: If the average (arithmetic mean) of p, q and r is 50 and the average   [#permalink] 19 Mar 2018, 09:52
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